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Artyom0805 [142]
3 years ago
11

Which of the following is the graph of f(x)= |x| reflected on the x-axis, translated 3units left, 4 units up, and dilated by a f

actor of 4?

Mathematics
1 answer:
FromTheMoon [43]3 years ago
8 0

Answer:

Step-by-step explanation:

Reflecting on the x-axis is multiplying the formula by a -1. That is, the resulting form is pointing up. When translated to the left 3 units, the tip of the graph is at the point (-3,0). Then when shifted 4 units up the tip is at (-3,4). Dilated by a factor of 4 will affect the values in x, but not the values in y. So the tip remains at the point (-3,4) which corresponds to the second graph

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Probability of stopping the machine when X < 9 is 0.0002

Probability of stopping the machine when X < 10 is 0.0013

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Step-by-step explanation:

There is a random binomial variable X that represents the number of units come off the line within product specifications in a review of n Bernoulli-type trials with probability of success 0.91. Therefore, the model is {15 \choose x} (0.91) ^ {x} (0.09) ^ {(15-x)}. So:

P (X < 9) = 1 - P (X \geq 9) = 1 - [{15 \choose 9} (0.91)^{9}(0.09)^{6}+...+{ 15 \choose 15}(0.91)^{15}(0.09)^{0}] = 0.0002

P (X < 10) = 1 - P (X \geq 10) = 1 - [{15 \choose 10}(0.91)^{10}(0.09)^{5}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0013

P (X < 11) = 1 - P (X \geq 11) = 1 - [{15 \choose 11}(0.91)^{11}(0.09)^{4}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0082

P (X < 12) = 1- P (X \geq 12) = 1 - [{15 \choose 12}(0.91)^{12}(0.09)^{3}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0399

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Probability of stopping the machine when X < 10 is 0.0013

Probability of stopping the machine when X < 11 is 0.0082

Probability of stopping the machine when X < 12 is 0.0399

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