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ozzi
3 years ago
5

Find the solution of the system of equations shown on the graph. Please and thank you :)

Mathematics
1 answer:
il63 [147K]3 years ago
5 0

Answer:

Hey there!

The solution is where the lines intersect, and here we see that would be (-4,3)

Hope this helps :)

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14

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2 years ago
Which equation can be used to calculate the surface area of the triangular prism net show below?
enyata [817]

Given:

Net of a triangular prism

To find:

Which equation can be used to calculate the surface area of the triangular prism.

Solution:

Using formulas:

Area of rectangle = length × width

Area of triangle = \frac{1}{2}\times b\times h

Area of left triangle = \frac{1}{2}\times 5\times 12

Area of right triangle = \frac{1}{2}\times 5\times 12

Area of bottom = 5 × 10

Area of Middle = 12 × 10

Area of top = 13 × 10

Surface area of triangular prism:

Surface area = Area of left triangle + Area of right triangle + Area of bottom + Area of middle + Area of top

                     $=\frac{1}{2}\times 5\times 10+\frac{1}{2}\times 5\times 10+5\times 10+12\times 10+13\times 10

Replace multiplication by brackets.

                     $=\frac{1}{2}(5)(10)+\frac{1}{2}(5)(10)+5( 10)+12( 10)+13( 10)

The equation can be used to calculate surface area of triangular prism is

$\frac{1}{2}(5)(10)+\frac{1}{2}(5)(10)+5( 10)+12( 10)+13( 10).

5 0
3 years ago
Read 2 more answers
Please I need help
Citrus2011 [14]

Answer:

x: C

y: A

z:

Step-by-step explanation:

In a 45-45-90 triangle, the hypotenuse is larger than either of the legs by a factor of \sqrt{2}. The length of x is therefore:

12\cdot \sqrt{2}=12\sqrt{2}

In a 30-60-90 triangle, the longer leg is larger than the shorter leg by a factor of \sqrt{3}. Therefore:

y=\dfrac{12}{\sqrt{3}}=\dfrac{12\sqrt{3}}{3}=4\sqrt{3}

The hypotenuse of the 30-60-90 triangle is twice larger than the smallest leg, so it has a length of 8\sqrt{3}.

By the pythagorean theorem, you can find z+y:

z+y=\sqrt{(12\sqrt{2})^2-12^2}=\sqrt{288-144}=12\\\\4\sqrt{3}+z=12 \\\\z=12-4\sqrt{3}

Hope this helps!

4 0
3 years ago
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