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2 years ago

12

PLZ HELP!! 20 points!

1 answer:

kolbaska11 [484]2 years ago

3 0

To find if a point is a solution to a system of equations, we need to plug in the x and y values of the point into each equation, and see if the equation is true.

Let's plug it into the first equation first:

-2(3) - 4(-2) might = 2
-6 + 8 = 2

The first equation is true.

Now, we need to check the second equation:

3(3) + 4(-2) might =8
9 - 8 does not = 8

Therefore, even if the point satisfies one equation, it does not satisfy the other. We can conclude that this is not a solution.

Hope this helps!

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Given z1 = startroot 2 endroot (cosine (startfraction 3 pi over 4 endfraction) i sine (startfraction 3 pi over 4 endfraction) )

vampirchik [111]

The subtraction of complex numbers $z_{1} -z_{2}$ is cos(π)+i sin(π).

Given $z_{1} =\sqrt{2}$ [cos(3π/4+i sin(3π/4) and $z_{2}$ =cos (π/2) +i sin(π/2)

We have to find the value of $z_{1} -z_{2}$ .

A complex number is a number that includes real number as well as a imaginary unit in which $i^{2} =1$ . It looks like a+ bi.

We have to first solve $z_{1} and z_{2}$ and then we will be able to find the difference.

$z_{1} =$ $\sqrt{2}$ [ cos (3π/4)+i sin (3π/4)]

$=\sqrt{2}$ [cos(π-π/4)+ i sin (π-π/4)]

= $\sqrt{2}$ [-cos(π/4)+sin (π/4)]

= $\sqrt{2}$ (-1/ $\sqrt{2}$ +1/ $\sqrt{2}$ )

= $\sqrt{2} *0$

=0

$z_{2} =$ cos(π/2)+i sin (π/2)

=0+i*1

=1

Now putting the values of $z_{1} and z_{2}$ ,

$z_{1} -z_{2} =0-1$

=-1

=-1+i*0

=cos (π)+i sin(π)

Hence the value of difference between $z_{1} and z_{2}$ is cos(π)+i sin(π).

Learn more about complex numbers at brainly.com/question/10662770

#SPJ4

3 0

1 year ago

Solve the inequality and enter your solution as an inequality in the box below,

Degger [83]

Answer:

x<3

Step-by-step explanation:

7 0

2 years ago

PLEASE HELP ASAP! Will give BRAINLIEST! Please answer correctly!<br> No guessing!

amm1812

Answer: f(x)=567(1/3)^x

Step-by-step explanation:

At x = 0 y = 567

at x = 1 y = 567 - 567(1/3)

at x = 2 y = 567 - 567(1/3)(1/3)

at x = 3 y = 567 - 567(1/3)(1/3)(1/3

7 0

2 years ago

What is the base of a 36in triangle

ExtremeBDS [4]

Your correct answer is 12.

3 0

2 years ago

Solve for x in this inequality. Show all your work and<br> graph your solution.<br> 4(x-3)<2x-4

maw [93]

Answer:

x<4

Step-by-step explanation:

To solve for x in the inequality equation, the terms should be rearranged such that x is on one side and integers are on the other side.

First, expand 4(x-3).

This will obtain:

$4x - 12 < 2x - 4$

Now, shift x terms and integers on each side.

$4x - 2x < - 4 + 12$

After simplifying, it will get:

$2x < 8$

Finally, we can solve for x.

$x < 4$

We can also draw the respective graph (please don't mind my drawings), where the area shaded in green is the range.

6 0

2 years ago