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Anarel [89]
2 years ago
7

Find the area of a rectangle with a length of 10 inches and width of 4 inches.

Mathematics
2 answers:
Pani-rosa [81]2 years ago
7 0
40 inches^2 is correct answer
kipiarov [429]2 years ago
3 0
10 x 4 = 40 inches squared
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10
beks73 [17]
The person above me is right. It’s A , you have to add
7 0
3 years ago
Which equations have the same value of x as Three-fifths (30 x minus 15) = 72? Select three options.
DanielleElmas [232]

Answer:

C 18 x minus 9 = 72

D 3 (6 x minus 3) = 72

E   x = 4.5

Step-by-step explanation:

Hope this helped

6 0
3 years ago
Read 2 more answers
I need help fast i don’t understand please give detailed explanation
alex41 [277]

Answer:

<4 = 63°

Step-by-step explanation:

32° + 31° = < 4 ( exterior angle of a triangle is equal to the sum of two opposite interior angles)

<4 = 63°

Hope it will help :)

5 0
3 years ago
The numerator of a certain fraction is four times the denominator. If 10 is added to both numerator and denominator the resultin
Ronch [10]
20/5 4x/x adding 10 to each 4x+10/x+10 =2 Multiple x+10 to each side 4x+10=2x+20 Then subtract and get 2x=10 Divide X=5 Now plug it back in 20/5
7 0
3 years ago
In the trapezoid ABCD ( AB ∥ CD ) point M∈ AD , so that AM:MD=3:5. Line l ∥ AB and going trough point M intersects diagonal AC a
geniusboy [140]

Answer:

BC:BN=8:3

Step-by-step explanation:

ABCD is a trapezoid and there is a point m which belongs to AD such that AM:MD=3:5.Line "l" parallel to AB intersects the diagonal AC at p and BD at N.

Now, we know that the parallel lines divide the transversal into the segments with equal ratio, therefore, BN:NC=AM:MD

But, BC= BN+NC

Therefore, BC:BN=(BN+NC):BN

⇒BC:BN=(3+5):3

⇒BC:BN=8:3


4 0
3 years ago
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