All categories

3 years ago

If the simple interest on $1,000 for 8 years is $ 480 then what is the interest rate?

Mathematics

1 answer:

Anestetic [448]3 years ago

7 0

Answer:

Step-by-step explanation:

Given data

Principal = $1,000

Time= 8 years

Simple interest= $480

The expression for the simple interest is

Simple interest= PRT/100

Substitute

480= 1000*R*8/100

Cross multiply

480= 8000R/100

480*100= 8000R

48000= 8000R

Divide both sides by 8000

R= 48000/8000

R=6%

You might be interested in

Pleaseeeee helpp<br>I'll give brainliest

Elodia [21]

The answer is 4...,.

3 0

3 years ago

A common assumption in modeling drug assimilation is that the blood volume in a person is a single compartment that behaves like

mixas84 [53]

Answer:

a) $\mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}$

b) $\mathbf{x = 2000 - 2000e^{-0.015t}}$

c) the steady state mass of the drug is 2000 mg

d) t ≅ 153.51 minutes

Step-by-step explanation:

From the given information;

At time t= 0

an intravenous line is inserted into a vein (into the tank) that carries a drug solution with a concentration of 500

The inflow rate is 0.06 L/min.

Assume the drug is quickly mixed thoroughly in the blood and that the volume of blood remains constant.

The objective of the question is to calculate the following :

a) Write an initial value problem that models the mass of the drug in the blood for t ≥ 0.

From above information given :

$Rate _{(in)}= 500 \ mg/L \times 0.06 \ L/min = 30 mg/min$

$Rate _{(out)}=\dfrac{x}{4} \ mg/L \times 0.06 \ L/min = 0.015x \ mg/min$

Therefore;

$\dfrac{dx}{dt} = Rate_{(in)} - Rate_{(out)}$

with respect to x(0) = 0

$\mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}$

b) Solve the initial value problem and graph both the mass of the drug and the concentration of the drug.

$\dfrac{dx}{dt} = -0.015(x - 2000)$

$\dfrac{dx}{(x - 2000)} = -0.015 \times dt$

By Using Integration Method:

$ln(x - 2000) = -0.015t + C$

$x -2000 = Ce^{(-0.015t)$

$x = 2000 + Ce^{(-0.015t)}$

However; if x(0) = 0 ;

Then

C = -2000

Therefore

$\mathbf{x = 2000 - 2000e^{-0.015t}}$

c) What is the steady-state mass of the drug in the blood?

the steady-state mass of the drug in the blood when t = infinity

$\mathbf{x = 2000 - 2000e^{-0.015 \times \infty }}$

x = 2000 - 0

x = 2000

Thus; the steady state mass of the drug is 2000 mg

d) After how many minutes does the drug mass reach 90% of its stead-state level?

After 90% of its steady state level; the mas of the drug is 90% × 2000

= 0.9 × 2000

= 1800

Hence;

$\mathbf{1800 = 2000 - 2000e^{(-0.015t)}}$

$0.1 = e^{(-0.015t)$

$ln(0.1) = -0.015t$

$t = -\dfrac{In(0.1)}{0.015}$

t = 153.5056729

t ≅ 153.51 minutes

4 0

3 years ago

3/5, 1/2,5/7 as a common

miskamm [114]

a common what? denominator?

4 0

3 years ago

The debate team has 15 members. Each member sold c coupon books as a fundraiser. Write an expression that shows the number of co

Aneli [31]

An expression that could represent 15 team members selling c coupon books would be 15c . This expression represents c amount of coupon books (which is the amount of coupon books sold per person) multiplied by the number of people that sold c amount of coupon books, which was 15.

6 0

3 years ago

Keith gets a weekly allowance of $12. If he saves 1/6 of his allowance each week, how much does he save in 5 weeks?

Leona [35]

Answer: 10 dollars

Step-by-step explanation: 1/6 of 12 is 2,and if he saves 2 dollars every week that means you just have to do 2 • 5,and you get your answer which is 10

8 0

4 years ago

If the simple interest on ​$1,000 for 8 years is ​$​ 480 then what is the interest​ rate?

If the simple interest on $1,000 for 8 years is $ 480 then what is the interest rate?