A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).
<h3>Calculate the vertices of ΔA'B'C':</h3>
Given that,
ΔABC : A(-6,-7), B(-3,-10), C(-5,2)
(x,y)→(x,y-3)
The vertices are:
- A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
- B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
- C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)
Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).
Learn more about translation rule:
brainly.com/question/15161224
#SPJ1
The first one is not a function due to the rule that there can not be more than one x, such as there is a repeated number 1 , 2 , 1 , 4 There should not be two
x = 1 terms.
Same the same rule applies to the second option as well as the last.
Your answer is C. or the third option
x= 6, 5, 4, 1
y=6, 4, 6, 2
Hope this Helps
Evaluate , I've had this question before and I got it right
Answer:
jejejjejejr
Step-by-step explanation:
uejejjejejjsjs
A quadratic function is a function of the form
. The
vertex,
of a quadratic function is determined by the formula:
and
; where
is the
x-coordinate of the vertex and
is the
y-coordinate of the vertex. The value of
determines if the <span>
parabola opens upward or downward; if</span>
is positive, the parabola<span> opens upward and the vertex is the
minimum value, but if </span>
is negative <span>the graph opens downward and the vertex is the
maximum value. Since the quadratic function only has one vertex, it </span><span>could not contain both a minimum vertex and a maximum vertex at the same time.</span>
