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3 years ago

Which graph represents the piecewise function?

Mathematics

1 answer:

zepelin [54]3 years ago

8 0

Answer:

C bottom left is ur answer

Step-by-step explanation:

heres a screenshot

Step-by-step explanation:

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Eight eagle stamps and two raccoon stamps cost $2.80. Three eagle stamps and four raccoon stamps cost $2.35. Find the cost of ea

nikklg [1K]

Answer:

Cost of each eagle stamp = $0.25

Cost of each racoon stamp = $0.4

Step-by-step explanation:

Given:

Cost of 8 eagle stamp and 2 racoon stamp = $2.80

Cost of 3 eagle stamp and 4 racoon stamp = $2.35

Find:

Cost of each stamp

Computation:

Assume;

Cost of each eagle stamp = e

Cost of each racoon stamp = r

So,

8e + 2r = 2.80........... Eq 1

3e + 4r = 2.35 ........... Eq 2

Eq 1 x 2

16e + 4r = 5.6 .........Eq3

Eq 3 - Eq 2

13e = 3.25

e = 0.25

Cost of each eagle stamp = $0.25

8e + 2r = 2.80

8(0.25) + 2r = 2.80

2 + 2r = 2.80

r = 0.4

Cost of each racoon stamp = $0.4

6 0

3 years ago

Cos 12° then sin = ?

d1i1m1o1n [39]

Cos 12 = sin (90 - 12) = sin 78

5 0

3 years ago

Hat word phrase can you use to represent the following algebraic expression: 7 + 4?

ExtremeBDS [4]

The sum of seven and four

3 0

3 years ago

Explain how you could use the Associative Property of Multiplication

Degger [83]

Answer:

5/(6*2*1/2)

Step-by-step explanation:

No matter where you put the parenthesis it stays the same answer. :)

8 0

3 years ago

I need help with this problem from the calculus portion on my ACT prep guide

LenaWriter [7]

Given a series, the ratio test implies finding the following limit:

$\lim _{n\to\infty}\lvert\frac{a_{n+1}}{a_n}\rvert=r$

If r<1 then the series converges, if r>1 the series diverges and if r=1 the test is inconclusive and we can't assure if the series converges or diverges. So let's see the terms in this limit:

$\begin{gathered} a_n=\frac{2^n}{n5^{n+1}} \\ a_{n+1}=\frac{2^{n+1}}{(n+1)5^{n+2}} \end{gathered}$

Then the limit is:

$\lim _{n\to\infty}\lvert\frac{a_{n+1}}{a_n}\rvert=\lim _{n\to\infty}\lvert\frac{n5^{n+1}}{2^n}\cdot\frac{2^{n+1}}{\mleft(n+1\mright)5^{n+2}}\rvert=\lim _{n\to\infty}\lvert\frac{2^{n+1}}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^{n+1}}{5^{n+2}}\rvert$

We can simplify the expressions inside the absolute value:

$\begin{gathered} \lim _{n\to\infty}\lvert\frac{2^{n+1}}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^{n+1}}{5^{n+2}}\rvert=\lim _{n\to\infty}\lvert\frac{2^n\cdot2}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^n\cdot5}{5^n\cdot5\cdot5}\rvert \\ \lim _{n\to\infty}\lvert\frac{2^n\cdot2}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^n\cdot5}{5^n\cdot5\cdot5}\rvert=\lim _{n\to\infty}\lvert2\cdot\frac{n}{n+1}\cdot\frac{1}{5}\rvert \\ \lim _{n\to\infty}\lvert2\cdot\frac{n}{n+1}\cdot\frac{1}{5}\rvert=\lim _{n\to\infty}\lvert\frac{2}{5}\cdot\frac{n}{n+1}\rvert \end{gathered}$

Since none of the terms inside the absolute value can be negative we can write this with out it:

$\lim _{n\to\infty}\lvert\frac{2}{5}\cdot\frac{n}{n+1}\rvert=\lim _{n\to\infty}\frac{2}{5}\cdot\frac{n}{n+1}$

Now let's re-writte n/(n+1):

$\frac{n}{n+1}=\frac{n}{n\cdot(1+\frac{1}{n})}=\frac{1}{1+\frac{1}{n}}$

Then the limit we have to find is:

$\lim _{n\to\infty}\frac{2}{5}\cdot\frac{n}{n+1}=\lim _{n\to\infty}\frac{2}{5}\cdot\frac{1}{1+\frac{1}{n}}$

Note that the limit of 1/n when n tends to infinite is 0 so we get:

$\lim _{n\to\infty}\frac{2}{5}\cdot\frac{1}{1+\frac{1}{n}}=\frac{2}{5}\cdot\frac{1}{1+0}=\frac{2}{5}=0.4$

So from the test ratio r=0.4 and the series converges. Then the answer is the second option.

8 0

2 years ago