Answer:
a·a-b·b
Step-by-step explanation:
What do you want us to answer??
Answer:
i think D
Step-by-step explanation:
im not great at math but yea i think D
Answer:
Step-by-step explanation:
From the given information, the symmetric equations for the line pass through(4, -5, 2) i.e (
) and are parallel to 
The parallel vector to the line i + zj+k = ai + bj + ck
Hence, the equation for the line is :

x = 4 + t
y = -5 + 2t
z = 2 + t
Thus, x, y, z = ( 4+t, -5+2t, 2+t )
The symmetric equation can now be as follows:



∴

Answer:
Step-by-step explanation: