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Aliun [14]
3 years ago
14

A roulette wheel has the numbers 1 through 36, 0, and 00. A bet on four numbers pays 8 to 1 (that is, if you bet $1 and one of t

he four numbers you bet comes up, you get back your $1 plus another $8). How much do you expect to win with a $1 bet on four numbers? HINT [See Example 4.] (Round your answer to the nearest cent.)
Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
4 0

Answer:

Lose $0.05

Step-by-step explanation:

There are 38 possible spots on the roulette wheel (numbers 1 to 36, 0 and 00).

If the player can choose four numbers on single $1 bet, his chances of winning (W) and losing (L) are as follows:

P(W) = \frac{4}{38} \\P(L) = 1-P(W) = 1-\frac{4}{38} \\P(L) = \frac{34}{38}

The expected value of the bet is given by the probability of winning multiplied by the payout ($8), minus the probability of losing multiplied by the bet cost ($1)

EV=\frac{4}{38}*\$8 -\frac{34}{38}*\$1\\EV= -\$0.05

On each bet, the player is expected to lose 5 cents ($0.05).

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Answer:

Using the Angle Addition Postulate, 20 + m∠DBC = 80. So, m∠DBC = 60° using the subtraction property of equality.

Step-by-step explanation:

If point D is the interior of angle ABC, then the angle addition postulate theory states that the sum of angle ABD and angle DBC is equals to angle ABC. The angle addition postulate is used to measure the resulting angle from two angles placed side by side.

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