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blondinia [14]
2 years ago
9

B) Calculate the area of the red triangle to find the area of the garden. Show your work

Mathematics
1 answer:
svetlana [45]2 years ago
8 0

Answer:

Solution given:

the area of the red triangle =½(a×b)unit²

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What is the greatest common factor of 12x 16x 8x
slega [8]

Answer:

4x

Step-by-step explanation:

The Factors of 12

1,12, 2,6 3,4

16

1,16 2,8 4,4

8

1,8 ,2,4

The highest factor they share is 4 so it would be the GCF. Then you would have to add the x back into the GCF

Hope It helped

8 0
3 years ago
How many times can 6 go into 58
swat32
58 ÷ 6 = 9/2/3

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4 0
3 years ago
Solve 3 -x = 243 -5 1/5 5
Paraphin [41]

Answer:

x=-243

Step-by-step explanation:

The equation is

-3^{-5}=\frac{1}{x}

Solve for x

we know that

-3^{-5}=-\frac{1}{3^{5}}=-\frac{1}{243}

substitute

-\frac{1}{243}=\frac{1}{x}

so

x=-243

3 0
3 years ago
Read 2 more answers
What’s the circumference, to this problem ?
Dafna11 [192]

Answer:

The formula to get the circumference of a circle is C=2*\pi * r but in this case we see that a diameter is being used therefore we can get rid of the 2 and the r because that is what the diameter and just replace d into there like this C=d*\pi.

We can then input the value and we get that C=1*\pi which then just narrows down to C=3.142.

<u><em>Hope this helps!  Let me know if you have any questions</em></u>

7 0
2 years ago
równanie zmiany prędkość autokaru poruszającego się po prostym odcinku szosy i rozpoczynającego hamowanie od szybkości 20m/s ma
Rasek [7]

Answer:

s = 22.5 m

Step-by-step explanation:

the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.

v (t) = 25 - 5 t

at t = 0 , v = 20 m/s

Let the distance is s.

s =\int v(t) dt\\\\s =\int (25 - 5t)dt\\\\s= 25 t - 2.5 t^2 \\

Let at t = t, the v = 20

So,

20 = 25 - 5 t

t = 1 s

So, s = 25 x 1 - 2.5 x 1 = 22.5 m

3 0
2 years ago
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