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2 years ago

5

ohnson High School has a total enrollment of 1829 students. Season tickets are sold for the basketball season and 604 students b

uy the tickets. About what percent of the student bo

1 answer:

Crank2 years ago

4 0

Only 33% of the students bought tickets.

There you go

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Whats 30 times 30 plus 45 minus 456

aleksandr82 [10.1K]

30 times 30 plus 45 minus 456 is 489

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2 years ago

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A park has a large circle painted in the middle of the playground area. The circle is divided into 4 equal sections, and each se

oee [108]

First you need to find the area of the whole circle. $\pi r^{2}$
The radius is given as 10, so just insert 10 into the equation of the area of a circle equation.
$Area = \pi 10^{2} Area = 100 \pi$
Putting $\pi$ after the 100 because that is what is commonly done.

Because the circle is then being split into 4 equal sections, we need to find 1/4 of the area of the whole circle to find the area of one of these sections.

Since the area of the whole circle is $100 \pi$ then we just divide that by 4,
leaving us with 25 $\pi$ and that is our final answer

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2 years ago

In 1875 an estimated twelve-and-a-half trillion locusts appeared in Nebraska.Write the number of locusts in scientific notation.

oksano4ka [1.4K]

Answer:

12.5 x 10^12

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12,500,000,000,000

12 zeroes following 12.5

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3 years ago

HELP WITH THIS EZ QUESTION

9966 [12]

Answer:

89

Step-by-step explanation:

$3+75t-16t^{2} =h\\\\$

we evaluate when t=2

$3+75(2)-16(2)^2=h\\\\3+150-64=h\\\\h=89$

so it's 89 feet

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3 years ago

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What are the coordinates of the centroid of a triangle with vertices A(−3, 1) , B(1, 6) , and C(5, 2) ? Enter your answer in the

kirza4 [7]

<u>ANSWER</u>: The centroid is (1,3)

<u>Explanation:</u>

The centroid is the intersection of the medians of the triangle.

So we need to find the equation of any two of the medians and solve simultaneously.

Since the median is the straight line from one vertex to the midpoint of the opposite side, we find the midpoint of any two sides.

We find the midpoint of AC using the formula;

$N=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

$N=(\frac{-3+5}{2}, \frac{1+2}{2})$

$N=(\frac{2}{2}, \frac{3}{2})$

$N=(1, \frac{3}{2})$

The equation of the median passes through $B(1,6)$ and $N=(1, \frac{3}{2})$ .

This line is parallel to the y-axis hence has equation

$x=1$ -------first median.

We also find the midpoint M of BC.

$M=(\frac{1+5}{2}, \frac{6+2}{2})$

$M=(\frac{6}{2}, \frac{8}{2})$

$M=(3, 4)$

The slope of the median, AM is

$Slope_{AM}=\frac{4-1}{3--3}$

$Slope_{AM}=\frac{3}{6}$

$Slope_{AM}=\frac{1}{2}$

The equation of the median AM is given by;

$y-y_1=m(x-x_1)$

We use the point M and the slope of AM.

$y-4=\frac{1}{2}(x-3)$

$2y-8=(x-3)$

$2y-x=-3+8$

$2y-x=5$ -------Second median

We now solve the equation of the two medians simultaneously by putting $x=1$ in to the equation of the second median.

$2y-1=5$

$2y=5+1$

$2y=6$

$y=3$

Hence the centroid has coordinates $(1,3)$

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2 years ago

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