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Molodets [167]
3 years ago
7

Another problem related to indefinite postponement is called ________. This occurs when a waiting thread (letâ s call this threa

d1) cannot proceed because itâ s waiting (either directly or indirectly) for another thread (letâ s call this thread2) to proceed, while simultaneously thread2 cannot proceed because itâ s waiting (either directly or indirectly) for thread1 to proceed. The two threads are waiting for each other, so the actions that would enable each thread to continue execution can never occur.
Computers and Technology
1 answer:
inn [45]3 years ago
5 0

Answer:

"Deadlock" is the right solution.

Explanation:

  • A deadlock seems to be a circumstance where certain (two) computer algorithms that share a similar resource essentially prohibit each other during manipulating the asset, leading to both programs withdrawing to operate.
  • This occurs when multiple transfers or transactions block everyone by maintaining locks onto assets that every other activity also needs.

So that the above is the correct answer.

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Codio Challenge Activity PythonWe are passing in a list of numbers. You need to create 2 new lists in your chart, then put all o
lilavasa [31]

Answer:

The python code is given below with lists defined.

Explanation:

import sys

def isEven(n) :

 return ((n % 2) == 0)  //for even items

numbers = sys.argv[1].split(',')

for i in range(0,len(numbers)):

 numbers[i]= int(numbers[i])

even = []

odd = []

for i in numbers:

   if isEven(i):

       even.append(i)  #adds i to even list if it is even

   else:

       odd.append(i)  #adds i to odd list if not even (odd)

print(odd)

print(even)

7 0
3 years ago
Whoever answers first gets lots of points
zimovet [89]
Firssstttttt ayyyyyyeeeeeeeeeeeee
8 0
3 years ago
Read 2 more answers
Survey data are collected by using all of these methods EXCEPT
castortr0y [4]

Answer:

Survey data are collected by using all of these methods except Field Research.

Explanation:

In field research data has been gathered from different experiments, qualitative analysis and observations of any event.

On the other hand, survey data can be collected from Following:

<u>structured interview</u><u>:</u>

where data can be gathered by interviews and analyzed it on quantitative basis.

<u>Face to face questionnaires:</u>

Data has been collected by asking questions directly from users in the form of interview.

<u>self-administered questionnaires</u>

In this research, questionnaire has been designed to asked question related to some topic without conducting interview.

8 0
4 years ago
HELP GENIUS Rank :))) DoNT answer If you don't know
RideAnS [48]

An instance in my life where I rendered services was when I worked in a grocery store.

The roles of entrepreneur include:

  • Allocating employees duties.
  • Improving standard of living.
  • Taking risks.

The three challenges that a young entrepreneur faces today include:

  • Financial instability.
  • Conflicts with education.
  • Lack of business skills.

The top three characteristics of an entrepreneur include:

  • Innovation.
  • Confidence
  • Risk taking

<h3>Who's an entrepreneur?</h3>

It should be noted that a entrepreneur is an individual who owns business and take risks.

The roles of entrepreneur include allocating employees duties, improving standard of living, and taking risks

Learn more about entrepreneur on:

brainly.com/question/353543

#SPJ1

3 0
1 year ago
Show the array that results from the following sequence of key insertions using a hashing system under the given conditions: 5,
sergejj [24]

Answer:

a) Linear probing is one of the hashing technique in which we insert values into the hash table indexes based on hash value.

Hash value of key can be calculated as :

H(key) = key % size ;

Here H(key) is the index where the value of key is stored in hash table.

----------

Given,

Keys to be inserted are : 5 , 205, 406,5205, 8205 ,307

and size of the array : 100.

First key to be inserted is : 5

So, H(5) = 5%100 = 5,

So, key 5 is inserted at 5th index of hash table.

-----

Next key to inserted is : 205

So, H(205) = 205%100 = 5 (here collision happens)

Recompute hash value as follows:

H(key) =(key+i) % size here i= 1,2,3...

So, H(205) =( 205+1)%100 = 206%100 = 6

So, key 205 is inserted in the 6th index of the hash table.

----------

Next Key to be inserted : 406

H(406) = 406%100 = 6(collision occurs)

H(406) =(406+1) %100 = 407%100 = 7

So, the value 406 is inserted in 7the index of the hash table.

-----------------

Next key : 5205

H(5205) = 5205%100 = 5(collision)

So, H(5205) = (5205+1)%100 = 6( again collision)

So, H(5205) = 5205+2)%100 = 7(again collision)

So, H(5205) = (5205+3)%100 = 8 ( no collision)

So, value 5205 is inserted at 8th index of the hash table.

-------------

Similarly 8205 is inserted at 9th index of the hash table because , we have collisions from 5th to 8th indexes.

-------------

Next key value is : 307

H(307) = 307%100 = 7(collision)

So, (307+3)%100 = 310%100 = 10(no collision)  

So, 307 is inserted at 10th index of the hash table.

So, hash table will look like this:

Key       index

5         5

205         6

406         7

5205 8

8205 9

307         10

b) Quadratic probing:

Quadratic probing is also similar to linear probing but the difference is in collision resolution. In linear probing in case of collision we use : H(key) = (key+i)%size but here we use H(key) =( key+i^2)%size.

Applying Quadratic probing on above keys:.

First key to be inserted : 5.

5 will go to index 5 of the hash table.

-------

Next key = 205 .

H(205) = 205%100 = 5(collision)

So. H(key)= (205+1^2)%100 = 6(no collision)

So, 205 is inserted into 6th index of the hash table.

--------

Next key to be inserted 406:

So, 406 %100 = 6 (collision)

(406+1^2)%100 = 7(no collision)

So, 406 is moved to 7th index of the hash table.

----------

Next key is : 5205

So, 5205%100 = 5 (collision)

So, (5205+1^2)%100 = 6 ( again collision)

So, (5205+2^2)%100 = 9 ( no collision)

So, 5205 inserted into 9th index of hash table.

-----------

Next key is 8205:

Here collision happens at 5the , 6the , 9th indexes,

So H(8205) = (8205+4^2)%100 = 8221%100 = 21

So, value 8205 is inserted in 21st index of hash table.

--------

Next value is 307.

Here there is collision at 7the index.

So, H(307) = (307+1^2)%100 = 308%100= 8.

So, 307 is inserted at 8the index of the hash table.

Key           Index

5                  5

205                  6

406                  7

5205                9

8205               21

307                   8

3 0
3 years ago
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