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Dmitry_Shevchenko [17]
3 years ago
8

What is 40 times 103

Mathematics
2 answers:
Vanyuwa [196]3 years ago
6 0

Answer:

4120

Step-by-step explanation:

40x103=4120

Katena32 [7]3 years ago
5 0

Answer:

4120

Step-by-step explanation:

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What are the next geometric sequences? The calculator won’t seem to give right answers
dalvyx [7]
5. the numbers are being multiplied by 4 each time, so the geometric sequence would be

an= 1/2(4) ^(n-1)

6. the numbers are being multiplied by 1/4 each time, so the geometric sequence would be

an= 32(1/4)^(n-1)

an in the formula is what ever term in the sequence.
32 or 1/2 is the a which is the first term in the sequence.
4 or 1/4 is the r in the sequence because it is the common ratio so what the equation was multiplied by to get the next term.
(n-1) is because when you are using this equation to solve for whatever term (an) you must subtract the first number in the sequence to get an accurate number

an you can input whatever number when trying to solve.
6 0
3 years ago
5.
horsena [70]
Need to know the radius.
7 0
3 years ago
Solve 4.62 + (−12.3).<br><br> 56.83<br> 5.85<br> −7.68<br> −16.92
ikadub [295]

The sum of the given decimal numbers is -7.68

<h3>Sum of decimal numbers</h3>

Decimal numbers are numbers that contains decimal points. Given the expression below;

4.62 + (−12.3).

Convert to fraction to have:

4.62 + (−12.3) = 462/100 - 123/10

Find the LCM

4.62 + (−12.3) = 462-1230/100

4.62 + (−12.3) = -768/100

4.62 + (−12.3) =-7.68

Hence the sum of the given decimal numbers is -7.68

Learn more on sum of numbers here; brainly.com/question/25734188

#SPJ1

4 0
1 year ago
A2+b2 = C2solve for a
lesantik [10]
a^2+b*2=c^2 

a^2+2b=c^2&#10;&#10;  \text{Regroup terms} 

a^2=c^2-2b&#10;  \text{Subtract 2b from both sides} 

a=\pm \sqrt{c^2-2b}  \text{Take the square root of both sides}

3 0
3 years ago
Pleaseeeee neeeddd helppp asappp
Rufina [12.5K]

ANSWER:

Segment TS is a Chord

If AR = 14 , then QS = 14 ×2 = 28

∆ATS is an Isosceles Triangle

<em><u>HOPE</u></em><em><u> </u></em><em><u>THIS</u></em><em><u> HELP</u></em><em><u> </u></em><em><u>YOU </u></em><em><u>,</u></em><em><u> FOR</u></em><em><u> ANY</u></em><em><u> QUESTION</u></em><em><u> PLEASE</u></em><em><u> ASK</u></em><em><u> </u></em><em><u>ME</u></em>

7 0
2 years ago
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