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luda_lava [24]
3 years ago
12

Two liters of water are poured into an empty vase shaped like an octagonal prism. The base area is 100 square centimeters. What

is the height of the water? (1 L = 1000 cm3)
Mathematics
1 answer:
Molodets [167]3 years ago
4 0

Answer: Height of the water is 20 cm.

Step-by-step explanation:

Since we have given that

Base area = 100 square cm

volume of vase shaped  like an octogonal prism = 2 liters

We need to find the height of water.

and 1 liter = 1000 cm³

2 liters = 2×1000 cm³

As we know the formula for "Volume":

Volume=\text{Base Area}\times height\\\\2\times 1000=100\times height\\\\height=\dfrac{2000}{100}\\\\height=20\ cm

Hence, height of the water is 20 cm.

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In the diagram below, x is a whole number. what is the smallest possible value for x?
lesya692 [45]

Answer:

The smallest possible value for x is 9\ units

Step-by-step explanation:

we know that

The <u>Triangle Inequality Theorem</u>. states that the sum of the lengths of any two sides of a triangle is greater than the length of the third side

so

x+x>17\\2x>17\\x>8.5\ units

The value of x must be greater than  8.5\ units

so

If x must be a whole number

therefore

The smallest possible value for x is 9\ units

3 0
2 years ago
According to the Rational Root Theorem, what are all the potential rational roots of f(x) = 15x11 – 6x8 + x3 – 4x + 3?
scoundrel [369]

we have

f(x) = 15x^{11} -6x^{8} + x^{3} - 4x + 3

we know that

<u>The Rational Root Theorem</u> states that when a root 'x' is written as a fraction in lowest terms

x=\frac{p}{q}

p is an integer factor of the constant term, and q is an integer factor of the coefficient of the first monomial.

So

in this problem

the constant term is equal to 3

and the first monomial is equal to 15x^{11} -----> coefficient is 15

So

possible values of p are 1, and\ 3

possible values of q are 1, 3, 5, and\ 15

therefore

<u>the answer is</u>

The all potential rational roots of f(x) are

(+/-)\frac{1}{15},(+/-)\frac{1}{5},(+/-)\frac{1}{3},(+/-)\frac{3}{5},(+/-)1,(+/-)3


3 0
3 years ago
Read 2 more answers
Find a nonzero vector orthogonal to the plane through the points: ????=(0,0,1), ????=(−2,3,4), ????=(−2,2,0).
ser-zykov [4K]

Answer:

The nonzero vector orthogonal to the plane is <-9,-8,2>.

Step-by-step explanation:

Consider the given points are P=(0,0,1), Q=(−2,3,4), R=(−2,2,0).

\overrightarrow {PQ}==

\overrightarrow {PR}==

The nonzero vector orthogonal to the plane through the points P,Q, and R is

\overrightarrow n=\overrightarrow {PQ}\times \overrightarrow {PR}

\overrightarrow n=\det \begin{pmatrix}i&j&k\\ \:\:\:\:\:-2&3&3\\ \:\:\:\:\:-2&2&-1\end{pmatrix}

Expand along row 1.

\overrightarrow n=i\det \begin{pmatrix}3&3\\ 2&-1\end{pmatrix}-j\det \begin{pmatrix}-2&3\\ -2&-1\end{pmatrix}+k\det \begin{pmatrix}-2&3\\ -2&2\end{pmatrix}

\overrightarrow n=i(-9)-j(8)+k(2)

\overrightarrow n=-9i-8j+2k

\overrightarrow n=

Therefore, the nonzero vector orthogonal to the plane is <-9,-8,2>.

8 0
3 years ago
Enter your answer and show all the steps that you use to solve this problem in the space provided.
shutvik [7]

Answer:

Step-by-step explanation:

we are given

(A)

(f×g)(x)=f(x)*g(x)

now, we can plug it

we can simplify it

(B)

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Firstly, we will find domain  of f(x) , g(x) and (fxg)(x)

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we know that f(x) is undefined at x=0

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∪

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Range:

Firstly, we will find range of f(x) , g(x) and (fxg)(x)

and then we can find common range

Range of f(x):

we know that range is all possible values of y for which x is defined

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∪

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6 0
3 years ago
What is 1,360/16 reduced to smallest form? (please hurry this assignment is due soon)
Keith_Richards [23]

Answer:

85/1

Step-by-step explanation:

because both numbers are divisible by 16

5 0
2 years ago
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