Answer:
Depth of the rain gutter is 8 inches
Step-by-step explanation:
Let’s assume ‘x’ is the depth of the rain gutter
Then the width of the rain gutter can be written as 16 - 2x
Cross sectional area
A = depth x width
Substitute values
A = x*(16 - 2x)
A = 16x – 2x^2
Now according to axis of symmetry for maximum area x = -b/2a
x = -16/2*(-2)
x = 4 inches depth of rain gutter, substitute the value of x to get
Width of rain gutter 16 – 2(4) = 8 inches
Area of the rain gutter for maximum water flow
A = 4 * 8
A = 32 square inch.
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Answer:
___________________
Step-by-step explanation:
Look at the photo below for the details.
:)
Answer:
y = -2 ( (x^2) + (2*x*5) + (5^2)) - 30
y = -2 ( x^2 + 10x + 25) - 30
y = -2x^2 - 20x - (2*25) - 30
y = -2x^2 - 20x - 50 - 30
y = -2x^2 - 20x - 80
The answer will be 0;7 and 2;112.
Answer:
Andre's Method is the only one that works
Step-by-step explanation:
Noah's method won't work because he doesn't follow the order of operations. You can pull the the 9 out first you have to distribute the 2 first.
Elena's method doesn't work because to eliminate the 18 you must use the reverse operation it must be added not subtracted.
Andre's Method is the only one that works
