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Neporo4naja [7]
4 years ago
6

A rain gutter is made from sheets of aluminum that are 16 inches wide by turning up the edges to form right angles. Determine th

e depth of the gutter that will maximize its​ cross- sectional area and allow the greatest amount of water to flow. What is the maximum​ cross-sectional area?
Mathematics
1 answer:
blsea [12.9K]4 years ago
8 0

Answer:

Depth of the rain gutter is 8 inches

Step-by-step explanation:

Let’s assume ‘x’ is the depth of the rain gutter

Then the width of the rain gutter can be written as 16 - 2x

Cross sectional area

A = depth x width

Substitute values

A = x*(16 - 2x)

A = 16x – 2x^2

Now according to axis of symmetry for maximum area x = -b/2a

x = -16/2*(-2)

x = 4 inches depth of rain gutter, substitute the value of x to get

Width of rain gutter 16 – 2(4) = 8 inches

Area of the rain gutter for maximum water flow

A = 4 * 8

A = 32 square inch.

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Step-by-step explanation:

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Find the equation of the least squares regression line. Show all calculations, and be sure to define any variables used.
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The cost of a fan is Rs 1,600. If Mrs. Khadka purchased it with 13% VAT, how muc did she pay for it? ​
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Answer:

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Step-by-step explanation:

Sp=Selling price

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2 years ago
How can you use number patterns to find the least common factor
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Answer:

The correct answer is: 360.

Explanation:

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2 * 2 * 2 * 3 * 5 = 120

You can get the above multiples as follows:

120/2 = 60

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30/2 = 15

15/3 = 5 (Since 15 cannot be divisible by 2, so we move to the next number)

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Take all the terms in the denominator for 120, you would get: 2 * 2 * 2 * 3 * 5 --- (1)

Second we can express 360 as follows:

360/2 = 180

180/2 = 90

90/2 =45

45/3 = 15 (Since 45 cannot be divisible by 2, so we move to the next number)

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Take all the terms in the denominator for 360, you would get: 2 * 2 * 2 * 3 * 3 * 5 --- (2)

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2*2*2*3*5 = Common between the two

3 = Remaining

Hence (2*2*2*3*5) * (3) = 360 = LCM (answer)

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3 years ago
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