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Lunna [17]
3 years ago
12

Help please!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Masja [62]3 years ago
6 0
4.91

Please don’t forget to leave a thanks
You might be interested in
I need help am I doing this right
disa [49]
No, you got the inequalities the wrong way.
In negative numbers, it is how much lower it is than 0. For example, -22 is 22 less than 0. And -2 is 2 less than 0. Here, -22 is actually less than -2 because it is farther below 0 than -2.
You can understand this better if you graph it on a number line.
So, -12 >-15. (-15 is 3 less than -12).
-1/3 >-1.
-2>-21.
8 0
4 years ago
May I have some help?
Sholpan [36]

Answer:

0 ÷ 3 = 0

Step-by-step explanation:

if x = 0 you put it in where the x is

8 0
3 years ago
What is 14 divided bye 3
bonufazy [111]

Answer:

4.66

14÷ 3 = 4 r 2

add 0 to 2 ( this attracts a decimal point in your answer)

20 ÷ 3 = 6r 2

and = 4.66

6 0
2 years ago
Read 2 more answers
One half of an apple pie is left for
vlada-n [284]

Answer: It will be 2/10

Step-by-step explanation:because if you divide the half part that you have into five and the other one two you will have 10 pieces that divided into 5 members will be 2

8 0
3 years ago
Pls help me, I don't know how to do it?:(​
FrozenT [24]

Answer and Step-by-step explanation:

Alot of these can be solved with the table up above the problems.

<h2>A, B, and C.</h2><h2></h2>

According to the table, every time a value has an exponent of 0, it would equal to 1. Since all A B and C values follow the 0 exponent, their value is 1.

<h2>D.</h2><h2 />

According to the table, when we have a negative exponent, the number gets turned into a fraction of \frac{1}{x^x}

Since our value is 9^-2, do as followed :

\frac{1}{9^2}

Solve what is 9^2 :

[\frac{1}{81} ]

<h2 /><h2>E.</h2><h2 />

\frac{1}{x^{-5} }

This question is different, since we have to go backwards, we have to switch the negative exponent to a positive exponent and rid the fraction.

x^5

<h2>F.</h2><h2 />

5a^3b^{-2}

Since we have one negative exponent, follow the fraction rule but instead of having one as the numerator, have 5a^3.

\frac{5a^3}{b^{2}}

<h2>Fill in the table :</h2><h2 />

-3^4 = -3*-3*-3*-3=-81

Since -3 is in parenthesis, we can rid the negative along with the parenthesis :

(-3)^4=3^4=3*3*3=81

Follow the negative exponent rule :

(-3)^{-4}=\frac{1}{(-3)^4} =\frac{1}{3^4} =\frac{1}{3*3*3*3}= \frac{1}{81}

Follow the negative exponent rule yet again :

-3^{-4}=-\frac{1}{3^4} =-\frac{1}{3*3*3*3} =-\frac{1}{81}

6 0
3 years ago
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