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Vitek1552 [10]
3 years ago
11

A Florida factory produces fishing reels at a rate of 800 per day, every day. In April, they are forced to cut their production

by 20% due to an aluminum shortage. A chain of sporting goods stores orders 20,000 fishing reels. since the factory will not be able to produce enough fishing reels in the 30 days of April to meet this order, how many reels will they be short?
Mathematics
2 answers:
Bingel [31]3 years ago
8 0

Multiply 800 to 4/5 to see how much they make per day.

800 * 4/5 = 640

So, they make 640 fishing reels per day.

Multiply this to 30:

640 * 30 = 19,200

So they will make 19,200 fishing reels in 30 days.

This is not enough for the order.

Xelga [282]3 years ago
3 0

Answer:

800  more reels

Step-by-step explanation:

Decrease of 20 percent means

800 * .20

160 reels less

800-160 = 640 reels produced

There are 30 days in April

days * 640 reel/ day

30 * 640 = 19200  reels produced in 30 days

They need 20000 reels

20000-19200 = 800  more reels

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<h3>Answer:  8/25</h3>

=======================================================

Explanation:

In a standard deck, there are 52 cards.

If this deck is missing the queen of hearts and 2 of clubs, then we really have 52-2 = 50 cards in the deck.

There are 4 aces and 13 spades. Those values add to 4+13 = 17, but we need to subtract off 1 to account for the ace of spades counted twice. We have 17-1 = 16 cards that are either an ace, a spade, or both.

Or you can think of it like saying 13 spades + 1 ace of hearts + 1 ace of diamonds + 1 ace of clubs = 16 cards total.

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The event space has A = 16 cards in it, while the sample space has B = 50 cards.

The probability we're after is A/B = 16/50 = 8/25

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2 years ago
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Let's say 1000 dollars was spent on all of these. That would mean 170 dollars and 240 were spent on food and entertainment respectivly. If we want to see how much of the total cost was spent on these things, we would have to add them and divide them by 1000, so:

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3 years ago
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Answer:

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Step-by-step explanation:

<u>Find zeros first:</u>

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