(3x^2-4+5)(x2-3x+2)? Multiply

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

3 0

Answer:

=(3x^2+1)(-x+2)

Step-by-step explanation:

(3x^2-4+5)(x*2-3x+2)=(3x^2+1)(-x+2)

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<u>Step-by-step explanation:</u>

$S_n=S_{n-2}\cdot (S_{n-1}-1)\quad \\\\S_1=2\quad given\\S_2=3\quad given\\S_3=S_1(S_2-1)\quad =2(3-1)\quad =4\\S_4=S_2(S_3-1)\quad =3(4-1)\quad =9\\S_5=S_3(S_4-1)\quad =4(9-1)\quad =32\\S_6=S_4(S_5-1)\quad =9(32-1)\quad =279\\S_7=S_5(S_6-1)\quad =32(279-1)\quad =8,896\\S_8=S_6(S_7-1)\quad =279(8896-1)\quad =2,481,705\\S_9=S_7(S_8-1)\quad =8896(2481705-1)\quad =22,077,238,784$