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stich3 [128]
4 years ago
8

The regular price of an item is $84. The item is on sale witha discount of $12. What is the discount rate.

Mathematics
1 answer:
sammy [17]4 years ago
5 0

Answer:

Discount = 14.3% (rounded up to one decimal place)

Step-by-step explanation:

The regular price of an item is $84

Discount = $12

Percentage discount = (Discount ÷ regular price) × 100

Percentage discount = \frac{12}{84} × 100 = 14.3% (rounded up to one decimal place)

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What is magnitude in maths ?
blondinia [14]

Answer:

In mathematics, the magnitude or size of a mathematical object is a property which determines whether the object is larger or smaller than other objects of the same kind. More formally, an object's magnitude is the displayed result of an ordering ( or ranking ) - of the class of objects to which it belongs.

8 0
3 years ago
Brian spends 1/3 on his wages on rent and 1/4 on food. If he makes £576 per week, how much money does he have left
natta225 [31]

Answer:

Step-by-step explanation:

Money spent on rent =1/3 of $576= 1/3×576= $192

Money spent on food = 1/4 of 576 = 1/4×576 =$144

Money left = 576-(192+144)=

=576-336= $240

5 0
3 years ago
100 points!!! Pre calculus. I need helpppppppppp
Fantom [35]

Answer:

We have function,

y = 3 - 6 \sin {}^{} (2x +  \frac{\pi}{2} )

Standard Form of Sinusoid is

y =  - 6 \sin(2x +  \frac{\pi}{2} )  + 3

Which corresponds to

y = a \sin(b(x + c))  + d

where a is the amplitude

2pi/b is the period

c is phase shift

d is vertical shift or midline.

In the equation equation, we must factor out 2 so we get

y =  - 6(2(x +  \frac{\pi}{4} )) + 3

Also remeber a and b is always positive

So now let answer the questions.

a. The period is

\frac{2\pi}{ |b| }

\frac{2\pi}{ |2| }  = \pi

So the period is pi radians.

b. Amplitude is

| - 6|  = 6

Amplitude is 6.

c. Domain of a sinusoid is all reals. Here that stays the same. Range of a sinusoid is [-a+c, a-c]. Put the least number first, and the greatest next.

So using that<em> rule, our range is [6+3, -6+3]= [9,-3] So our range</em> is [-3,9].

D. Plug in 0 for x.

3 - 6 \sin((2(0) +  \frac{\pi}{2} )

3 - 6 \sin( \frac{\pi}{2} )

3 - 6(1)

3 - 6

=  - 3

So the y intercept is (0,-3)

E. To find phase shift, set x-c=0 to solve for phase shift.

x +  \frac{\pi}{4}  = 0

x =  -  \frac{\pi}{4}

Negative means to the left, so the phase shift is pi/4 units to the left.

f. Period is PI, so use interval [0,2pi].

Look at the graph above,

6 0
3 years ago
8c + c = what please help me i am doing test and need answer right now. like 4rl
lianna [129]

Answer: 8c

Step-by-step explanation:

We do not know the value of c or the other c.

So, the answer to the question is 8c. Hope it helped.

8 0
3 years ago
Read 2 more answers
I need help with this problem. <br>​
Zina [86]

Answer:

(1,4)

Step-by-step explanation:

Let's this of y=\sqrt{x} which is it's parent function.

How do we get to y=-\sqrt{x-1}+4 from there?

It has been reflected about the a-axis because of the - in front of the square root.

It has been shifted right 1 unit because of the -(1) in the square root.

It has been moved up 4 units because of the +4 outside the square root.

In general:

y=a(x-h)^2+k has the following transformations from the parent:

Moved right h units if h is positive.

Moved left h units if h is negative.

Moved up k units if k is positive.

Moved down k units if k is negative.

If a is positive, it has not been reflected.

If a is negative, it has been reflected about the x-axis.

a also tells us about the stretching factor.

The parent function has a starting point at (0,0).  Where does this point move on the new graph?

It new graphed was the parent function but reflected over x-axis and shifted right 1 unit and moved up 4 units.

So the new starting point is (0+1,0+4)=(1,4).

6 0
3 years ago
Read 2 more answers
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