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azamat
3 years ago
13

What is the cube root of -1000p^12q^3

Mathematics
2 answers:
sergeinik [125]3 years ago
8 0
The answer would be -10p64q^1 
since -10^3(p^4)^3 (q^1)^3 is -1000p^12q^3
Alina [70]3 years ago
4 0

Answer:

(-10p^{4}q)

Step-by-step explanation:

we have

\sqrt[3]{-1000p^{12}q^{3}}

we know that

-1000p^{12}q^{3}=(-10)^{3} (p^{4})^{3}(q)^{3}=(-10p^{4}q)^{3}

substitute in the expression

\sqrt[3]{-1000p^{12}q^{3}}=\sqrt[3]{(-10p^{4}q)^{3}}=(-10p^{4}q)

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