Answer: u got a course hero account ?
Step-by-step explanation:
Step-by-step explanation:
Draw diagonal AC
The triangle ABC has sides 17 and 25
Say AB is 17, BC is 25
Draw altitude on side BC from A , say h
h = 17 sin B
Area = 25*17 sin B = 408
sin B = 24/25
In ∆ ABC
Cos B = +- 7/25
= 625 + 289 — b^2 / 2*25*17
b^2 = 914 — 14*17 = 676
b = 26
h = 17*24/25 = 408/25 = 16.32
Draw the second diagonal BD
In ∆ BCD, draw altitude from D, say DE =h
BD^2 = h^2 + {(25 + sqrt (289 -h^2) }^2
BD^2 = 16.32^2 + (25 + 4.76)^2
= 885.6576 + 266.3424
BD = √ 1152 = 33.94 m
Slope = 1
y-intercept = -3, which can be expressed as (0,-3).
y - y_1 = m(x - x_1)
y -(-3) = 1(x - 0)
y + 3 = x
The slope-intercept form is
y = x - 3.
The standard form is Ax + By = C.
y = x - 3
3 = x - y
Done.
Answer:
Creo que es de la siguiente forma
Step-by-step explanation:
---------------------------------------------------------------------------------------------------
----------------------------------------------------------------------------------------------------------
-
-
---
-
-
-
-
-
2.0² * π = 12.56637...
12.56637... * 9.6 = 120.6371579...
120.6371579.. / π = 38.4
√38.4 = 6.196773354... --> the radius of circle A dialated by 9.6 = 6.2 cm
