27 x 38 = 1026
33 x 37 = 1221
1026 + 1221 = 2247
2247 / 2 = 1123.5
<span>2≤x≤8</span>
<span>−4≤<span>f′</span>(x)≤5</span>
f is continuous in differentable on [2,8] so we know there is c btw 2 and 8 such that
<span><span>f′</span>(c)=<span><span>f(8)−f(2)</span><span>/8−2</span></span></span>
And we know
<span>−4≤<span>f′</span>(c)≤5</span>
=> we have
<span>−4≤ <span><span>f(8)−f(2)</span><span>/8−2</span></span> ≤<span>5</span></span>
Answer:
Scatter plot one is not a good fit so answer is first picture to the left in a top row( see the pattern). Second plot is a good fit so the answer is the last right picture in a top row( points around x axis).
Step-by-step explanation:
A random scatter of points in the residual plot indicates that the linear function is a good fit for the given data. A non random residual plot indicates that the chosen function is not a good fit.
Answer:maybe 0.75
Step-by-step explanation:
Answer:
Step-by-step explanation:
you have to add a table
