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dolphi86 [110]
3 years ago
7

A diver is currently at an elevation of -380 feet. Write an absolute value statement to express the diver's distance, in feet, f

rom sea level. Then, interpret the result within the context of the situation.
Mathematics
1 answer:
spin [16.1K]3 years ago
4 0

Answer:

The diver is at |- 380| = 380 feet distance from the sea level.

Step-by-step explanation:

Here, the diver is at 380 feet below the sea level.

So, the diver is at |- 380| = 380 feet distance from the sea level.

Here, the absolute value function y = |x| gives the value only irrespective of its sign.

Now, in this case the distance of the diver from the sea level is required and whether it is above or below sea level is not important. (Answer)

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SIMPLIFY<br> −6u2v−uv2−22u2v2.
nignag [31]

Answer:

-uv • (22uv + 6u + v)

hope it helpes

8 0
3 years ago
Does anyone know this ? i'm stuck.. i'll give you brainliest and 15 points !! show work.
madam [21]

Answer:

x = 7

Step-by-step explanation:

The angle adjacent to the 70 degree angle is also 70 degrees.  We assume that there are four 90-degree angles in the center of the figure.  Thus, 8x - 36 + 70 + 90 = 180 (the sum of the interior angles is 180 degrees).

Solving  8x - 36 + 70 + 90 = 180 for x:

              8x - 36 = 20, or 8x = 56.

Dividing both sides by 8 yields x = 7.

5 0
3 years ago
Simplify into one logarithm 2 log x + 3 log y
const2013 [10]
If a logarithm has a coefficient, then the coefficient can also be written as the exponent of the input of the logarithm. In other words, if you have the logarithm alog(x), that is equal to log(x^a). So the expression can be rewritten:

log(x^2)+log(y^3)

If tow logarithms of the same bases are added together that is equal to the logarithm of the product of the inputs of the two original logarithms. In other words, given log(x)+log(y), it can also be written as log(xy). So the expression can be combined into one logarithm:

log(x^2 * y^3)
8 0
3 years ago
b. Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box.
Ainat [17]

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

<u>Step-by-step explanation:</u>

Here we have , Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box. The third box contained two more pounds than the first box. The last box contained one-fourth the amount in the second box. We need to find How much candy was in each box. Let's find out:

We have a total of 65 pounds of candy ! Let in first box we have x pounds so , second box contained twice the amount of the first box i.e.

⇒ 2x

The third box contained two more pounds than the first box i.e.

⇒ x+2

The last box contained one-fourth the amount in the second box i.e.

⇒ (\frac{1}{4})2x = \frac{x}{4}

Therefore , Sum of pounds of candy are :

⇒ \frac{x}{2} +x+2+2x+x=65

⇒ \frac{x}{2} +4x=63

⇒ \frac{9x}{2}=63

⇒ x=63(\frac{2}{9} )

⇒ x=14

Therefore , Candy in each box is :

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

8 0
4 years ago
Can you guys give me a serious answer please?
grin007 [14]

Answer:

800 bacteria

Step-by-step explanation:

Answer of this question depend upon number of hours at the end of day

Let Take Full Day of 24 hrs

Colby bacteria will doubled 12 times ( doubled once in 2hrs => 24/2 = 12)

Colby bacteria at end of day = 50 * 2¹²

Jaquan bacteria will doubled 8 times ( doubled once in 3hrs => 24/3 = 8)

Let say Jaquan bacteria at start  of Day = J

Jaquan bacteria at end of day = J * 2⁸

Equating Both

J * 2⁸ = 50 * 2¹²

=> J = 50 * 2⁴

=> J = 50 * 16

=> J = 800

Jaquan will start  with 800 Bacteria

4 0
2 years ago
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