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Kay [80]
2 years ago
8

Giving it all out, leaving brainly soon. points, thanks, and 5 stars​

Mathematics
2 answers:
NISA [10]2 years ago
7 0
Answer :
Why lol ????
kobusy [5.1K]2 years ago
3 0

Answer:

Why leaving dude, Don't leave brainly. Really Miss You LO!

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Help Plss <br>Linear equation is also called​
vladimir2022 [97]

Answer:

degree equation

Step-by-step explanation:

I hope this helped you!

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2 years ago
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3.<br> -4r – 6 + 6r + 9 = 29
SIZIF [17.4K]

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r=13

Step-by-step explanation:

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Which of the following functions best describes this graph?
sweet-ann [11.9K]

Answer: A. y=x²-9x+20

Step-by-step explanation:

As we can see from the graph there are two x-intercepts: (4,0) (5,0)

The easiest way we can do, is we plug these two values into each of the choices.

A. y=x²-9x+20

(4, 0) YES

(5,0) YES

B. y=x²-8x+18

(4, 0) NO

(5, 0) NO

C. y=x²+9x+20

(4, 0) NO

(5, 0) NO

D. y=x²+x-12

(4, 0) NO

(5, 0) NO

Therefore, the answer should be y=x²-9x+20

Hope this helps!! :)

Please let me know if you have any questions

8 0
2 years ago
In the local frisbee league, teams have 7 members and each of the 4 teams takes turns hosting tournaments. At each tournament, e
mars1129 [50]

There are 4 teams in total and each team has 7 members. One of the team will be the host team.

Tournament committee will be made from 3 members from the host team and 2 members from each of the three remaining teams. Selecting the members for tournament committee is a combinations problem. We have to select 3 members out 7 for host team and 2 members out of 7 from each of the remaining 3 teams.

So total number of possible 9 member tournament committees will be equal to:

7C3 \times 7C2 \times 7C2 \times 7C2\\ \\  = 324135

This is the case when a host team is fixed. Since any team can be the host team, there are 4 possible ways to select a host team. So the total number of possible 9 member tournament committee will be:

9 \times 324135\\ \\  =2917215

Therefore, there are 2917215 possible 9 member tournament committees

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2 years ago
Please help I am very confused!
Ad libitum [116K]

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pls add me as a friend pls

Step-by-step explanation:

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