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3 years ago

How many 4-digit numbers are neither multiples of 2 nor multiples of 5?

Mathematics

1 answer:

Gwar [14]3 years ago

4 0

There are 10,000 total four-digit numbers (1000 through 9999).

Multiples of 2 end in 0, 2, 4, 6, and 8. There are 9*10*10*5 = 4500 four-digit multiples of 2.

Multiples of 5 end in 0 or 5. There are 9*10*10*2 = 1800 four-digit multiples of 5.

There is redundancy between the two sets of numbers, namely those that end in 0, which are both multiples of 2 and 5. There are 9*10*10*1 = 900 four-digit multiples of both 2 and 5.

Then there are 4500 + 1800 - 900 = 5400 total four-digit numbers that are either multiples of 2 or 5, which means the remaining 4600 numbers are neither multiples of 2 nor 5.

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Solve the following using the elimination or substitution method. Show all work.

ki77a [65]

Jim has 28 nickels and 37 dimes in his pocket. which is determined by the substitution method.

<h3>What is the equation?</h3>

The term "equation" refers to mathematical statements that have at least two terms with variables or integers that are equal.

Let the number of nickels would be n

Let the number of dimes would be d

As per the given question,

d + n = 65 ....(i)

0.10d + 0.05n = 5.10 ....(ii)

From equation (i),

d + n = 65

d + n - n = 65 - n

d = 65 - n

Substitute in for the equation(ii): d = 65 - n

0.10(65 - n) + 0.05n = 5.10

6.5 - 0.10n + 0.05n = 5.10

6.5 - 0.05n = 5.10

6.5 - 0.05n - 6.5 = 5.10 - 6.5

- 0.05n = -1.4

n = 28

This means there are 28 nickels

Substitute the value of n = 28 in the equation (i),

d + n = 65

d + 28 = 65

d = 37

So there are 37 dimes

Thus, Jim has 28 nickels and 37 dimes in his pocket.

Learn more about the equation here:

brainly.com/question/10413253

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3 0

1 year ago

Read 2 more answers

Why is it important to use a device like a random number table in a simulation?

Jet001 [13]

I don’t think it’s the second or third one I’m narrowing it down to the first or maybe fourth

I think the answer is the first one though

5 0

3 years ago

Two particles travel along the space curves r1(t) = t, t2, t3 r2(t) = 1 + 2t, 1 + 6t, 1 + 14t . Find the points at which their p

GuDViN [60]

Answer:

A) points at which paths intersect : (1,1,1) ; (2,4,8)

B) DNE

Step-by-step explanation:

A) To find the points in which the particle paths intersect, it is necessary to find the values of t for which the three components of both vectors are equal:

$t_1=1+2t_2\\\\t_1^2=1+6t_2\\\\t_1^3=1+14t_2$

you replace t1 from the first equation in the second equation:

$(1+2t_2)^2=1+6t_2\\\\1+4t_2+4t_2^2=1+6t_2\\\\4t_2^2-2t_2=0\\\\t_2(2t_2-1)=0\\\\t_2=0\\\\t_2=\frac{1}{2}$

Then, for t2 = 0 and t2=1/2 you obtain for t1:

$t_1=1+2(0)=1\\\\t_1=1+2(\frac{1}{2})=2$

Hence, for t1=1 and t2=0 the paths intersect. Furthermore, for t1=2 and t2=1/2 the paths also intersect.

The points at which the paths intersect are:

$r_1(1)=(1,1,1)=r_2(0)=(1,1,1)\\\\r_1(2)=(2,4,8)=r_2(\frac{1}{2})=(2,4,8)$

B) You have the following two trajectories of two independent particles:

$r_1(t)=(t,t^2,t^3)\\\\r_2(t)=(1+2t,1+6t,1+14t)$

To find the time in which the particles collide, it is necessary that both particles are in the same position on the same time. That is, each component of the vectors must coincide:

$t=1+2t\\\\t^2=1+6t\\\\t^3=1+14t$

From the first equation you have:

$t=1+2t\\\\t=-1$

This values does not have a physical meaning, then, the particle do not collide

answer: DNE

5 0

3 years ago

What is between 280 and 560?

nikitadnepr [17]

420 would be the middle number.

Hoped I Could Help:)

3 0

3 years ago

As part of a science experiment, Sam recorded the four values shown in the table, but one of them got smudged on his paper. He r

denpristay [2]

Answer:

D) 4

Step-by-step explanation:

−9 + 12 + (unknown) + −8 = −1

Start by going through and testing each option

−9 + 12 + 2 + −8 =

3 + 2 + −8 =

5 + −8 =

−3

−3 ≠ −1

A) 2 is not possible.

−9 + 12 + −2 + −8 =

3 + −2 + −8 =

1 + −8 =

−7

−7 ≠ −1

B) −2 is not possible.

−9 + 12 + −4 + −8 =

3 + −4 + −8 =

−1 + −8 =

−9

−9 ≠ −1

C) −4 is not possible.

From this, D is looking like the answer. But to be sure, test it.

−9 + 12 + 4 + −8 =

3 + 4 + −8 =

7 + −8 =

−1

−1 = −1

D) 4 is the answer.

5 0

3 years ago