Answer:
no solution Ф
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<h3>
Answers: </h3><h3>
Q1 = 6</h3><h3>
Q3 = 21</h3>
The data is already sorted for us. If it wasn't, then you would have to write the values from smallest to largest.
The median is the middle most value 9 (in slot 4)
The median separates the data into two halves, which I'll call the lower and upper half
lower half = {4,6,8}
upper half = {13,21,31}
The median of the lower half is 6, and this is the value of Q1.
The median of the upper half is 21. This is the value of Q3
Answer:
roast beef is 48
Step-by-step explanation:
vegetarian is 32
The first place and 15th place are already decided, so we have to find the number of <span>different ways that the </span>other<span> 13 students can line up, in the places from 2 to 14.</span>
2nd place can be any one of 13 people. For each of those . . .
3rd place can be any one of 12 people. For each of those . . .
4th place can be any one of 11 people. For each of those
13th place can be any one of 2 people. For each of those
14th place has to be the one student who is left.
Total number of ways that 13 students can line up in places 2 through 14 is
(13 x 12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1)
<span>That number is called "thirteen factorial". The number is </span>6,227,020,800<span> . </span>
<span>When you write it in math, you write it like this:</span><span>13</span>
We can express that as a fraction, taking into account that dividing by 4 is equivalent as multipliying by 1/4 (because the 4 is in the lower part as denominator that is). So we have:
(7/6)/4 = <span>(7/6)(1/4)
</span>and now we only have to multiply numerators and denominators:
= 7*1/6*4
= 7/24
that is the result.