What do you need what is the question
D= # of dimes
q= # of quarters
QUANTITY EQUATION:
d + q= 64
COST EQUATION:
0.10d + 0.25q= $9.25
STEP 1:
multiply quantity equation by -0.10 to be able to eliminate the d term in step 2
(-0.10)(d + q)= (-0.10)(64)
-0.10d - 0.10q= -6.40
STEP 2:
add equation from step 1 to cost equation to eliminate the d term and solve for q
Add
0.10d + 0.25q= $9.25
-0.10d - 0.10q= -6.40
0.15q= 2.85
divide both sides by 0.15
q= 19 quarters
STEP 3:
substitute q value in step 2 into either original equation to find d value
d + q= 64
d + 19= 64
subtract 19 from both sides
d= 45 dimes
CHECK:
0.10d + 0.25q= $9.25
0.10(45) + 0.25(19)= 9.25
4.50 + 4.75= 9.25
9.25= 9.25
ANSWER: There are 45 dimes and 19 quarters.
Hope this helps! :)
The subtracton property of equality allows you to subtract the same amount from both sides of an equation without changing the truth of the equation.
Answer:
3(x - 5)(x + 1).
Step-by-step explanation:
3x^2 - 12x - 15
Dividing through by 3:
= 3(x^2 - 4x - 5)
We need 2 numbers whose sum is -4 and whose product = -5. That is -5 and +1 , so the factors are:
3(x - 5)(x + 1).
