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ioda
3 years ago
13

Solve the formula please!!!!!!!!

Mathematics
2 answers:
Rashid [163]3 years ago
4 0

Answer:

Option A. is the right choice.

Step-by-step explanation:

\frac{1}{3}b^2h=V\\\\hb^2=3V\\\\b^2=\frac{3V}{h}\\\\b=\sqrt{\frac{3V}{h}}

Best Regards!

spin [16.1K]3 years ago
4 0
1. Multiply 3 to both sides to get rid of 1/3
2. Divide h to get b alone
3. Square b to get b alone
Your answer ends up being letter A
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(6x – 2y = 5<br> 4x – 3y = 5
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Answer:

This is not a real question rephrase

Step-by-step explanation:

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2 years ago
Create a system of equations for this situation. A store sells bracelets for $10 and rings for $15. On Monday they sold 30 items
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Answer:

10x + 15y = 450

Step-by-step explanation:

A store sells bracelets for $10 and rings for $15.

Sold 30 items.

They counted the money they made $450.

x = bracelets

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3 years ago
A machine used to fill​ gallon-sized paint cans is regulated so that the amount of paint dispensed has a mean of ounces and a st
11111nata11111 [884]

Complete question is;

A machine used to fill gallon-sized paint cans is regulated so that the amount of paint dispensed has a mean of 128 ounces and a standard deviation of 0.20 ounce. You randomly select 35 cans and carefully measure the contents. The sample mean of the cans is 127.9 ounces. Does the machine need to be? reset? Explain your reasoning.

(yes/no)?, it is (very unlikely/ likely) that you would have randomly sampled 35 cans with a mean equal to 127.9 ?ounces, because it (lies/ does not lie) within the range of a usual? event, namely within (1 standard deviation, 2 standard deviations 3 standard deviations) of the mean of the sample means.

Answer:

Yes, we should reset the machine because it is unusual to have a mean equal to 127.9 from a random sample of 35 as the mean of 127.9 doesn't fall within range of a usual event with 2 standard deviations of the mean of the sample means.

Step-by-step explanation:

We are given;

Mean: μ = 128

Standard deviation; σ = 0.2

n = 35

Now, formula for standard error of mean is given as;

se = σ/√n

se = 0.2/√35

se = 0.0338

Normally, the range of values should be within 2 standard deviations of mean. In this case, normal range of values will be;

μ ± 2se = 128 ± 0.0338

This gives; 127.9662, 128.0338

So, Yes, we should reset the machine because it is unusual to have a mean equal to 127.9 from a random sample of 35 as the mean of 127.9 doesn't fall within range of a usual event with 2 standard deviations of the mean of the sample means.

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3 years ago
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See the attached photo for answer

7 0
3 years ago
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