In the plane, we have everywhere. So in the equation of the sphere, we have
which is a circle centered at (2, -10, 0) of radius 4.
In the plane, we have , which gives
But any squared real quantity is positive, so there is no intersection between the sphere and this plane.
In the plane, , so
which is a circle centered at (0, -10, 3) of radius .
Answer:
A. 18x + 15
Step-by-step explanation:
For this problem, we will simply simplify the given expression:
5(4x + 3) - 2x
= 5*4x + 5*3 - 2x
= 20x + 15 - 2x
= 20x - 2x + 15
= 18x + 15
Cheers
Answer:
3/2-u
Step-by-step explanation:
You need to break the question down by seeing that is it asking for u less than something so that means subtraction. You then see the quotient of 2 and 3 so then you put 3 over 2 to divide and then put your subtract 2 onto it