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3 years ago

FIND THE VALUE OF X AND Y.(ordered pairs)(x+y,0)=(8,x-y)

Mathematics

1 answer:

Aliun [14]3 years ago

5 0

Step-by-step explanation:

We know that...

x+y (from the first pair) corresponds to 8(in the second pair)..

0 (from the first pair) corresponds to x-y (in the second pair)..

Hence,

$x + y = 8 \\ x - y = 0$

By simply adding the two equations we get,

$2x = 8 \\ x = 4$

Hence,

By substituting x=4, we get that y=4

Hence,

x=y=4

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Komok [63]

Answer:

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Step-by-step explanation:

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2 years ago

Simplify: (2x - 4) - (6x + 6)

tatiyna

<h3>Further explanation</h3>

Order of Operations in Mathematics follow this following rule :

Parentheses
Exponents
Multiplication and Division
Addition and Subtraction

This rule is known as the PEMDAS method.

Let us tackle the problem!

$(2x - 4) - (6x +6) = 2x - 4 - 6x - 6$ ⇒ open parenthesis

$(2x - 4) - (6x +6) = 2x - 6x - 4 - 6$ ⇒ rearrange term

$(2x - 4) - (6x +6) = (2 - 6)x - 10$ ⇒ factorize

$(2x - 4) - (6x +6) = -4x - 10$

$\large {\boxed {(2x - 4) - (6x +6) = -2( 2x + 5 ) } }$

<h2>Another Example :</h2>

$(2x - 4) + (6x +6) = 2x - 4 + 6x + 6$ ⇒ open parenthesis

$(2x - 4) + (6x +6) = 2x + 6x - 4 + 6$ ⇒ rearrange term

$(2x - 4) + (6x +6) = (2 + 6)x + 2$ ⇒ factorize

$(2x - 4) + (6x +6) = 8x + 2$

$\large {\boxed {(2x - 4) + (6x +6) = 2( 4x + 1 ) } }$

<h3>Learn more</h3>

Infinite Number of Solutions : brainly.com/question/5450548
System of Equations : brainly.com/question/1995493
System of Linear equations : brainly.com/question/3291576

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Linear Equations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point

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3 years ago

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sergiy2304 [10]

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3 years ago

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(4x-3)(2x^2-7x+1) what is the product of this please help!

goblinko [34]

Answer:

$8x^{3}-34x^{2}+25x-3$

Step-by-step explanation:

In order to solve this problem, lets take the two terms in the binomial (4x and -3) and, for each one, multiply them by each term in the trinomial (2x^2, -7x, and 1):

$(4x-3)(2x^{2}-7x+1)$

$(4x*2x^{2})+(4x*-7x)+(4x*1)+(-3*2x^{2})+(-3*-7x)+(-3*1)$

$8x^{3}+(-28x^{2})+4x+(-6x^{2})+21x+(-3)\\$

$8x^{3}-28x^{2}+4x-6x^{2}+21x-3$

Let's combine like terms to get our final answer:

$8x^{3}-28x^{2}-6x^{2}+4x+21x-3$

$8x^{3}-34x^{2}+25x-3$

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3 years ago

Find the value of x , if log₂ [log₅ (log₃x)] = 0

Lina20 [59]

$\log_2 (\log_5( \log_3x)) = 0\\
D:x>0 \wedge \log_3x>0 \wedge \log_5(\log_3x)>0\\
D:x>0\wedge x>1 \wedge\log_3x>1\\
D:x>1 \wedge x>3\\
D:x>3\\
\log_5(\log_3x)=1\\
\log_3x=5\\
x=3^5\\
x=243$

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3 years ago

FIND THE VALUE OF X AND Y.(ordered pairs)(x+y,0)=(8,x-y)​

FIND THE VALUE OF X AND Y.(ordered pairs)(x+y,0)=(8,x-y)