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Verizon [17]
3 years ago
11

FIND THE VALUE OF X AND Y.(ordered pairs)(x+y,0)=(8,x-y)​

Mathematics
1 answer:
Aliun [14]3 years ago
5 0

Step-by-step explanation:

We know that...

x+y (from the first pair) corresponds to 8(in the second pair)..

0 (from the first pair) corresponds to x-y (in the second pair)..

Hence,

x + y = 8 \\ x - y = 0

By simply adding the two equations we get,

2x = 8 \\ x  = 4

Hence,

By substituting x=4, we get that y=4

Hence,

x=y=4

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3

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Svet_ta [14]
<h2>Answer:</h2>

\boxed{x=1, \y=-1, \ z=2}

<h2>Step-by-step explanation:</h2>

We will use the Gaussian elimination method to solve this problem. To do so, let's follow the following steps:

Step 1: Let's multiply first equation by −2. Next, add the result to the second equation. So:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\~~ x&-~~~~~ y&+~~~~ z&~=~4\end{array}

Step 2: Let's multiply first equation by −1. Next, add the result to the third equation. Thus:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&-~~~3~ y&+~~2~ z&~=~7\end{array}

Step 3: Let's multiply second equation by −35, Next, add the result to the third equation. Therefore:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&&+~~\frac{ 1 }{ 5 }~ z&~=~\frac{ 2 }{ 5 }\end{array}

Step 4: solve for z, then for y, then for x:

\frac{ 1 }{ 5 } ~ z & = \frac{ 2 }{ 5 } \\ \\ \boxed{z & = 2}

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Answer:

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