1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Umnica [9.8K]
3 years ago
13

The volume of a cylinder is given by the formula v =

title="\pi r^{2} h" alt="\pi r^{2} h" align="absmiddle" class="latex-formula">. Find the height h if the volume is 35 cubic feet, the radius is and 7/22 and\pi is 22/7.
Mathematics
1 answer:
pashok25 [27]3 years ago
3 0

Answer:

<h2>height = 110 feet </h2>

Step-by-step explanation:

From the question

Volume of the cylinder is given by

<h3>v = \pi  {r}^{2} h</h3>

To find the height first make h the subject

That's divide both sides by πr²

We have

<h3>h =  \frac{v}{\pi  {r}^{2} }</h3>

From the question

v = 35 ft³

r = 7 / 22

π = 22/7

Substitute the values into the above formula and solve for the height

That's

<h3>h = \frac{35}{ \frac{22}{7} \times  ({ \frac{7}{22} })^{2}  }  \\  =   \frac{35}{ \frac{22}{7} \times  \frac{49}{484}  }  \\  =  \frac{35}{ \frac{7}{22} }  \\  \ = 35 \div  \frac{7}{22}  \\  = 35 \times  \frac{22}{7}  \\  = 5  \times 22</h3>

We have the final answer as

<h3>110 feet</h3>

Hope this helps you

You might be interested in
3 in3.62 stands for 3
harkovskaia [24]

Answer:

true???????????????

6 0
2 years ago
Help. I need help with these questions ( see image).<br> Please show workings.
Andrew [12]

9514 1404 393

Answer:

  4)  6x

  5)  2x +3

Step-by-step explanation:

We can work both these problems at once by finding an applicable rule.

  \text{For $f(x)=ax^n$}\\\\\lim\limits_{h\to 0}\dfrac{f(x+h)-f(x)}{h}=\lim\limits_{h\to 0}\dfrac{a(x+h)^n-ax^n}{h}\\\\=\lim\limits_{h\to 0}\dfrac{ax^n+anx^{n-1}h+O(h^2)-ax^n}{h}=\boxed{anx^{n-1}}

where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.

This can be referred to as the <em>power rule</em>.

Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:

  lim[h→0](f(x+h)-f(x))/h = 2ax +b

__

4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.

5. The gradient of x^2 +3x +1 is 2x +3.

__

If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.

3 0
2 years ago
PLEASE HELP!
ycow [4]

Answer:

I dont know what sin is

Step-by-step explanation:

3 0
2 years ago
2x + 7 = 27 or 3 + 3x = 30
Leokris [45]

Step-by-step explanation:

2x + 7 = 27 OR 3 + 3x = 30.

2x = 27 - 7 OR 3x = 30 - 3

2x = 20 OR 3x = 27

x = 20/2 OR x = 27/3

x = 10 OR x = 9

5 0
2 years ago
Is it C or no? Can u help please
Westkost [7]
 the answer is Probably C.

7 0
3 years ago
Other questions:
  • Rico tried to solve an equation step by step.
    8·2 answers
  • 36 is 72% of what number
    8·2 answers
  • Please help. This is summer homework that's due in 2 days!
    15·1 answer
  • The traffic capacity of a highway is v vehicles per minute. Which expression represents the highway’s capacity in vehicles per h
    10·2 answers
  • Starting with 2 marked points, A and B, precisely describe the straightedge and compass moves required to construct the triangle
    6·1 answer
  • PLEASE ANSWER I NEED IT FOR MY TEST I GIVE BRAINLIEST TO WHO ANSWERS!!!!
    6·2 answers
  • Which of the following functions shows an initial amount of $15 and an increase of 35%
    10·1 answer
  • 27. Solve for x?<br><br> A 25 <br> B 16 <br> C 27<br> D 9
    7·1 answer
  • Which relation is a function?
    7·1 answer
  • The ratio of hydrogen to oxygen in a plant sample is 18:12. The sample has 42 units of oxygen.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!