The function is

, and according to the description of the function in the problem statement, we have the following:
at t=0 after being thrown (that is, at initial time), the height of the ball is calculated by h(0) as follows:

(ft), which is the initial height, as expected.
At t=1 (sec), the height would be

.
etc.
The path is parabolic, as we know by seeing that the function is a quadratic polynomial function. This function has been given in factored form as well. From that we can see that the zeros of the function are t=7 and t=-2.
This means that at t=7 sec, the height h is 0, which means that the ball has hit the ground. t=-2 has no significance in the context of our problem so we just neglect it.
Answer: B) 7 sec
B. Yes, because it passes the vertical line test.
F(x)=2(3)-5
f(x)=6-5
f(x)=1
No because it would be
if you knew that
ax^2+bx+c was a trinomial square, then the factored form would be

or

so
if w^2-9w+81 is perfect square, factored form is either

or

aka

or
expand them
(x+9)^2=x^2+18x+81, wron middle term
(x-9)^2=x^2-18x+81 wrong
so it is not
i just want tp know what app this is or what yall are learning over here