Given side length "a" and angle "A", calculate the diagonals<span><span>
p = square root [( 2a^2 - 2a^2 cos(A) )]
</span>q = </span><span>square root [( 2a^2+ 2a^2 cos(A) )]</span>
http://www.calculatorsoup.com/calculators/geometry-plane/rhombus.php
side = 36
cos (32) = 0.84805
p = <span>small diagonal = </span>
<span>
<span>
<span>
19.8457652914
</span>
</span>
</span>
<span><span>
</span>
</span>
q =
large diagonal =
<span>
<span>
<span>
69.2108777578
</span>
</span>
</span>
Answer:
Let's start with part B. if it was originally 10 cm tall and it goes up 0.5 cm. each day, then we know that to go up one cm it needs two days. With that information we can say that 8*2 = 16. So it needs 17 days to go up 8.5 cm which would make it 18.5 cm tall.
Step-by-step explanation:
f(x) = 0.5x + 10
0.5x + 10 = 18.5
0.5x = 18.5 - 10
0.5x = 8.5
x = 8.5/0.5
x = 17 days
Let's solve for h.
h
p
=
p
3
+
4
p
2
−
2
Step 1: Divide both sides by p.
h
p
p
=
p
3
+
4
p
2
−
2
p
h
=
p
3
+
4
p
2
−
2
p
Answer:
h
=
p
3
+
4
p
2
−
2
p
