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3 years ago

The explicit rule for an arithmetic sequence is an=

Mathematics

1 answer:

VashaNatasha [74]3 years ago

8 0

Answer:

an = a1 + (n - 1)d.

Step-by-step explanation:

an = a1 + (n - 1)d where a1 = the first term and d = the common difference.

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I’m really confused please help

Vikentia [17]

Answer:

(2). <em>b - (a + c)i </em>

Step-by-step explanation:

$i^{7}$ = [( i )²]³ × i = ( - 1)³ i = - i

$i^{16}$ = $((i)^2)^{8} = ( - 1)^{8} = 1$

$((i)^2)^{10}$ × i = i

a(- i ) + b( 1 ) - c( i ) = - ai + b - ci = <em>b - (a + c)i</em>

4 0

3 years ago

If two lines intersect in the same plane to form a right angle, what can be concluded?

zheka24 [161]

That it forms an angle of 90 degrees

5 0

3 years ago

Simplify the following expression.

nydimaria [60]

Answer:

-70x, 26y^3, -3z

Step-by-step explanation:

The way to solve this is by combining like terms. The terms we have given to us include x, y^3, and z. As a result, we will group terms based on these variables.

1. Find all the terms with each variable.

* -35x, -35x

* 23y^3, 3y^3

* -3z

2. Combine like terms.

* -35x + (-35x) = -35x - 35x = -70x

* 23y^3 + 3y^3 = 26y^3

* -3z + 0 = -3z

7 0

2 years ago

Read 2 more answers

A professional baseball player hits a homerun on a .75kg baseball. The ball accelerated at a rate of 1200m/s2. How much force di

brilliants [131]

Answer:

The force the player hit the ball with is 900 N

Step-by-step explanation:

Given;

mass of the baseball, m = 0.75 kg

acceleration of the ball, a = 1200 m/s²

The force the player hit the ball with is given by the following equations;

F = ma (based on Newton's second law of motion)

where;

F is the applied force

m is mass of the baseball

a is the acceleration of the baseball

F = ma

F = (0.75 x 1200)

F = 900 N

Therefore, the force the player hit the ball with is 900 N

3 0

3 years ago

Assuming boys and girls are equally likely, find the probability of a couple having a baby girl when their sixth child is born

Ivanshal [37]

Answer: The required probability of having 6th girl is 0.5.

Step-by-step explanation: Given that boys and girls are equally likely.

We are to find the probability of a couple having a baby girl when their sixth child is born, given that the first five children were all girls.

Since the events of having a boy and a girl are independent of each other, so

the probability of having 6th girl dose not depend on the birth of the first five girls.

We know that there are only two possible cases (either a boy or girl will born).

So, sample space, S = {G, B} and the event E of having a girl is, E = {G}.

That is, n(S) = 2 and n(E) = 1.

Therefore, the probability of event E is given by

$P(E)=\dfrac{n(E)}{n(S)}=\dfrac{1}{2}=0.5.$

Thus, the required probability of having 6th girl is 0.5.

3 0

3 years ago