Assuming boys and girls are equally likely, find the probability of a couple having a baby girl when their sixth child is born
1 answer:
Answer: The required probability of having 6th girl is 0.5.
Step-by-step explanation: Given that boys and girls are equally likely.
We are to find the probability of a couple having a baby girl when their sixth child is born, given that the first five children were all girls.
Since the events of having a boy and a girl are independent of each other, so
the probability of having 6th girl dose not depend on the birth of the first five girls.
We know that there are only two possible cases (either a boy or girl will born).
So, sample space, S = {G, B} and the event E of having a girl is, E = {G}.
That is, n(S) = 2 and n(E) = 1.
Therefore, the probability of event E is given by
Thus, the required probability of having 6th girl is 0.5.
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Answer:
Option A is the correct answer.
Explanation:
The given pyramid has 3 lateral triangular side as shown below.
Base of triangle = 12 unit
We need to find perpendicular.
By Pythagoras theorem we have
Perpendicular² = 10²-6²
Perpendicular = 8 unit
So area of 1 lateral triangle = 1/2 x Base x Perpendicular.
= 1/2 x 12 x 8 = 48 unit²
Area of lateral side = 3 x 48 = 144 unit²
Option A is the correct answer.
Answer:
a)
And if we solve for we got:
b) False
The reason is because we don't satisfy the following relationship:
We have that:
c) False
In order to satisfy independence we need to have the following condition:
And for this case we don't satisfy this relation since:
Step-by-step explanation:
For this case we have the following probabilities given:
Part a
We want to calculate the following probability:
And we can use the total probability rule given by:
And if we solve for we got:
Part b
False
The reason is because we don't satisfy the following relationship:
We have that:
Part c
False
In order to satisfy independence we need to have the following condition:
And for this case we don't satisfy this relation since: