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Brut [27]
3 years ago
15

Assuming boys and girls are equally​ likely, find the probability of a couple having a baby girl when their sixth child is​ born

, given that the first five children were all girls.
Mathematics
1 answer:
Ivanshal [37]3 years ago
3 0

Answer:  The required probability of having 6th girl is 0.5.

Step-by-step explanation:  Given that boys and girls are equally likely.

We are to find the probability of a couple having a baby girl when their sixth child is​ born, given that the first five children were all girls.

Since the events of having a boy and a girl are independent of each other, so

the probability of having 6th girl dose not depend on the birth of the first five girls.

We know that there are only two possible cases (either a boy or girl will born).

So, sample space, S = {G, B}  and the event E of having a girl is, E = {G}.

That is, n(S) = 2 and n(E) = 1.

Therefore, the probability of event E is given by

P(E)=\dfrac{n(E)}{n(S)}=\dfrac{1}{2}=0.5.

Thus, the required probability of having 6th girl is 0.5.

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If x−2/4=2, then x=10
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Answer:

True.

Step-by-step explanation:

\frac{(10)-2}{4}=2\\\\\frac{8}{4}=2\\\\2=2

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1-5. Evaluate each absolute value expression. Can you help me with this and if you can explain it to me thanks you
mihalych1998 [28]

Well when it comes to absolute value remember that whatever number is inside the two straight lines will always come out as a positive.

a) [54] would still be 54

b)-[-7 3/5] so first you get the absolute value which comes out to 7 3/5 but because there is a negative sign out side of the two parallel lines, the answer would be -7 3/5

c)[3]-[-1] the absolute value of 3 is 3 and the absolute value of -1 is 1. So the expression would be 3-1 which comes out to 2

d)[2.2-5.13] 2.2-5.13 would equal -2.93 but since it is in the absolute value, the answer would come out as 2.93

Hope this helps!

3 0
3 years ago
A 4 metre ladder is placed against a vertical wall.
Black_prince [1.1K]

Answer:

Original position: base is 1.5 meters away from the wall and the vertical distance from the top end to the ground let it be y and length of the ladder be L.

Step-by-step explanation:

By pythagorean theorem, L^2=y^2+(1.5)^2=y^2+2.25 Eq1.

Final position: base is 2 meters away, and the vertical distance from top end to the ground is y - 0.25 because it falls down the wall 0.25 meters and length of the ladder is also L.

By pythagorean theorem, L^2=(y -0.25)^2+(2)^2=y^2–0.5y+ 0.0625+4=y^2–0.5y+4.0625 Eq 2.

Equating both Eq 1 and Eq 2: y^2+2.25=y^2–0.5y+4.0625

y^2-y^2+0.5y+2.25–4.0625=0

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0.5y=1.8125

y=1.8125/0.5= 3.625

Using Eq 1: L^2=(3.625)^2+2.25=15.390625, L=(15.390625)^1/2= 3.92 meters length of ladder

Using Eq 2: L^2=(3.625)^2–0.5(3.625)+4.0625

L^2=13.140625–0.90625+4.0615=15.390625

L= (15.390625)^1/2= 3.92 meters length of ladder

<em>hope it helps...</em>

<em>correct me if I'm wrong...</em>

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Answer:

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