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ValentinkaMS [17]
3 years ago
12

Pro

Mathematics
1 answer:
Anna11 [10]3 years ago
3 0

Answer:

explain

Step-by-step explanation:

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How many solutions does the equation 2x-6=6+2x
Alex_Xolod [135]

Answer:

2 solutions

Step-by-step explanation:

Since the equations are not equal, they provide two solutions. Negative numbers provide no solutions. If they are equal to zero, they have one solution.


5 0
3 years ago
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Hey pplz who else goes to TOPS :):):)
gtnhenbr [62]

Answer:

nope not i

Step-by-step explanation:

5 0
3 years ago
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A pet store holds training classes for dogs. The store has two different training programs. The first program charges a $35 memb
GrogVix [38]

The programs cost the same for 7 classes.

Given, no. of classes is represented by c, no. of dogs is represented by d, no. of hours is represented by h, the no. of programs is represented by p and the total cost is represented by t.

The first program charges $35 membership fee and $5 for each class.

The second program charges only $10 for each class.

Now the total cost say t_{1}, for first program can be written in equation form as,

t_{1} =35+5c,  here c is the no. of classes.

Similarly, the total cost say t_{2} , for second program can be written in equation form as,

t_{2} =10c.

We have to find out the no. of classes for which the two programs cost the same.

according to the question,

t_{1} =t_{2}

35+5c=10c\\10c-5c=35\\5c=35\\c=7

Hence for 7 of classes the programs cost the same.

For more details follow the link:

brainly.com/question/4042361

3 0
2 years ago
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Evaluate the surface integral ∫sf⋅ ds where f=⟨2x,−3z,3y⟩ and s is the part of the sphere x2 y2 z2=16 in the first octant, with
skad [1K]

Parameterize S by the vector function

\vec s(u,v) = \left\langle 4 \cos(u) \sin(v), 4 \sin(u) \sin(v), 4 \cos(v) \right\rangle

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.

Compute the outward-pointing normal vector to S :

\vec n = \dfrac{\partial\vec s}{\partial v} \times \dfrac{\partial \vec s}{\partial u} = \left\langle 16 \cos(u) \sin^2(v), 16 \sin(u) \sin^2(v), 16 \cos(v) \sin(v) \right\rangle

The integral of the field over S is then

\displaystyle \iint_S \vec f \cdot d\vec s = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \vec f(\vec s) \cdot \vec n \, du \, dv

\displaystyle = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \left\langle 8 \cos(u) \sin(v), -12 \cos(v), 12 \sin(u) \sin(v) \right\rangle \cdot \vec n \, du \, dv

\displaystyle = 128 \int_0^{\frac\pi2} \int_0^{\frac\pi2} \cos^2(u) \sin^3(v) \, du \, dv = \boxed{\frac{64\pi}3}

8 0
2 years ago
X to the 5 power times x to the 8 power time x to the 0 power
serg [7]

idk i am in 6th grade idk

3 0
3 years ago
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