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Sliva [168]
3 years ago
7

There are 125 sheep and 5 dogs in a flock how old is the shepherd?

Mathematics
1 answer:
kirill [66]3 years ago
5 0

Answer:

25 years old

hope this helps  

~savannah:))

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Find m∠C. Put the answer below.<br> m∠C =
andreev551 [17]

Step-by-step explanation:

Use Pythagorean Theorem to find the missing side

a = q

b = e

c = c

So,

a^{2} +b^{2} =c^{2}

to

7^{2} +3^{2} =x^{2}

which equals x = \sqrt{58}

and

m∠Q + m∠E+ m∠C = 180° ( which is m∠A + m∠B + m∠C= 180°)

find all the sides so when they are all added together they equal 180°
Sorry, I couldn't give you the answer but I hope this helped?

3 0
3 years ago
What advantages does the graphing calculator have when it comes to finding the solution to a system of linear equations? Explain
Mashcka [7]
For this case you have the following advantages:
 
 1)
you can see the graph of both equations

 2) you can see where the equations intersect

 3) the point of intersection represents the solution to the system of equations.

 4) You can solve the problem in much less time than doing it by hand

 5) You can find very accurate solutions.
4 0
3 years ago
Read 2 more answers
Which statement is true about the effects of the transformations on the graph of function f to obtain the graph of function g. g
IgorC [24]

Answer:

The correct option is D

D) The graph of function f(x) is shifted right 3 units and up 4 units

Step-by-step explanation:

Lets the function be y = f(x)

To shift the graph 3 units to the right, we add -3 to the x term of the function:

Function becomes y' = f(x-3)

Then to shift the graph up by 4 units, we add -4 to the y term of the function:

Function becomes:

y - 4 = f(x-3)

y = f(x-3) +4

g(x) = f(x-3) +4

Hence the correct option is D, as the graph is shifted to the right by 3 units and also shifted up by 4 units

3 0
3 years ago
The tangent of the graph of y=<img src="https://tex.z-dn.net/?f=e%5E%7Bax%7D" id="TexFormula1" title="e^{ax}" alt="e^{ax}" align
bearhunter [10]

a) The tangent to y=e^{ax} at x=p has slope

y' = ae^{ax} \implies y'(p) = ae^{ap}

and y=e^{ap} at this point. It passes through the origin, so its equation is

y - 0 = ae^{ap} (x - 0) \implies y = ae^{ap} x

It also passes through the point (p,e^{ap}) on the curve, so

y - e^{ap} = ae^{ap} (x - p) \implies y = e^{ap} + ae^{ap} x - ape^{ap}

By substitution,

ae^{ap} x = e^{ap} + ae^{ap} x - ape^{ap} \implies e^{ap} = ape^{ap} \implies ap=1 \\\\ \implies \boxed{p=\dfrac1a}

b) The normal to y=e^{ax} at x=2p has slope

-\dfrac1{y'(2p)} = -\dfrac1{ae^{2ap}} = -1 \implies ae^{2ap} = 1

It follows that

ae^{2ap} = ae^2 = 1 \implies \boxed{a = \dfrac1{e^2} \text{ and } p = e^2}

c) The tangent line equation is then

y = \dfrac1{e^2} e^1 x \implies \boxed{y = \dfrac xe}

7 0
2 years ago
Kristen worked 39 hours in 6 days
Fittoniya [83]
<h2>39/6 = 6.5</h2><h2 /><h2>6 hours 30 minutes</h2>
5 0
3 years ago
Read 2 more answers
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