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3 years ago

Find the perimeter and area

Mathematics

2 answers:

Sedbober [7]3 years ago

8 0

Answer:

the area is 13.5 inches squared and the perimeter is 16 inches

Step-by-step explanation:

because if you add 4.5 + 4.5 + 3.5 + 3.5 that equals 16

and if you multiply 4.5 by 3 equals 13.5 I hope I'm right I hope this helped

Vesna [10]3 years ago

5 0

Answer:

P = 16 in, A = ²⁷/₂ in² or 13¹/₂ in²

Step-by-step explanation:

The perimeter is found by adding up all of the side lengths.

P = 4¹/₂ + 4¹/₂ + 3¹/₂ + 3¹/₂

P = 4 + 4 + 3 + 3 + 2

P = 16 in

The area of a parallelogram is found by multiplying the base and the height.

A = 3 × 4¹/₂

A = 3 × ⁹/₂

A = ²⁷/₂ in² or 13¹/₂ in²

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Maggie has a container in the shape of a right prism. The formula for its surface area is SA = Ph + 2B. Solve for h.

mart [117]

Answer:

Step-by-step explanation:

We have been given a formula for the surface area of a container in shape of right prism. We are asked to solve for h for our given formula.

First of all, we will switch sides for our given equation as:

Now, we will subtract 2B from both sides of our equation.

Now, we will divide both sides of our equation by P.

Therefore, option A is the correct choice.

PLS MARK BRAINLIST

8 0

3 years ago

Add.

Phoenix [80]

The answers is 11x+2 I’m pretty sure. I can’t tell if your x3 was an exponent or multiplying.

4 0

4 years ago

I need help plz answer before Monday 26th

IRISSAK [1]

The first one is 3 8/10 are not rotten because 5 3/10- 1 5/10 = 3 8/10

The second one needs information on the strawberries which it dosen't show on the picture.

Hope this helped a bit.

7 0

3 years ago

Umm I don’t remember this please help. I will give correct answer brainliest

VikaD [51]

Answer:

Option D

Step-by-step explanation:

$F=\frac{9}{5}C+32\\\\F-32=\frac{9}{5}C \\\\5(F-32)=9C\\\\\frac{5(F-32)}{9}=C \\\\C=\frac{5}{9}( {F-32})$

For F=77°F

$C=\frac{5}{9}(F-32) \\\\C=\frac{5}{9}(77-32)\\\\C=\frac{5}{9}(45)\\\\C=\frac{225}{9} \\\\C=25$

7 0

3 years ago

Question regarding logarithms.

Eddi Din [679]

$5^{x-2}-7^{x-3}=7^{x-5}+11\cdot5^{x-4}\\\\5^{x-2}-7^{x-2-1}=7^{x-2-3}+11\cdot5^{x-2-2}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\5^{x-2}-\dfrac{7^{x-2}}{7^1}=\dfrac{7^{x-2}}{7^3}+11\cdot\dfrac{5^{x-2}}{5^2}\\\\5^{x-2}-\dfrac{1}{7}\cdot7^{x-2}=\dfrac{1}{343}\cdot7^{x-2}+\dfrac{11}{25}\cdot5^{x-2}\\\\-\dfrac{1}{7}\cdot7^{x-2}-\dfrac{1}{343}\cdot7^{x-2}=\dfrac{11}{25}\cdot5^{x-2}-5^{x-2}\\\\\left(-\dfrac{1}{7}-\dfrac{1}{343}\right)\cdot7^{x-2}=\left(\dfrac{11}{25}-1\right)\cdot5^{x-2}$

$\left(-\dfrac{49}{343}-\dfrac{1}{343}\right)\cdot7^{x-2}=-\dfrac{14}{25}\cdot5^{x-2}\\\\-\dfrac{50}{343}\cdot7^{x-2}=-\dfrac{14}{25}\cdot5^{x-2}\qquad\text{multiply both sides by}\ \left(-\dfrac{25}{14}\right)\\\\\dfrac{50\cdot25}{343\cdot14}\cdot7^{x-2}=5^{x-2}\qquad\text{divide both sides by}\ 7^{x-2}\\\\\dfrac{25\cdot25}{343\cdot7}=\dfrac{5^{x-2}}{7^{x-2}}\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}$

$\dfrac{5^2\cdot5^2}{7^3\cdot7}=\left(\dfrac{5}{7}\right)^{x-2}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\\dfrac{5^4}{7^4}=\left(\dfrac{5}{7}\right)^{x-2}\\\\\left(\dfrac{5}{7}\right)^4=\left(\dfrac{5}{7}\right)^{x-2}\iff x-2=4\qquad\text{add 2 to both sides}\\\\\boxed{x=6}$

6 0

3 years ago

Read 2 more answers

Find the perimeter and area​

Find the perimeter and area