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garri49 [273]
3 years ago
5

Is 300,998 greater or less than 300899

Mathematics
2 answers:
Romashka-Z-Leto [24]3 years ago
8 0
300998 is greater than 300899
xeze [42]3 years ago
7 0
300,998 is greater than 300,899
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10)
Naddika [18.5K]

Answer:

i

Step-by-step explanation:

5 0
3 years ago
(y - 2)2 = y2 – 6y + 4<br> Is this statement true or false?
trasher [3.6K]
<h3>Answer: False</h3>

==============================================

Explanation:

I'm assuming you meant to type out

(y-2)^2 = y^2-6y+4

This equation is not true for all real numbers because the left hand side expands out like so

(y-2)^2

(y-2)(y-2)

x(y-2) .... let x = y-2

xy-2x

y(x)-2(x)

y(y-2)-2(y-2) ... replace x with y-2

y^2-2y-2y+4

y^2-4y+4

So if the claim was (y-2)^2 = y^2-4y+4, then the claim would be true. However, the right hand side we're given doesn't match up with y^2-4y+4

--------------------------

Another approach is to pick some y value such as y = 2 to find that

(y-2)^2 = y^2-6y+4

(2-2)^2 = 2^2 - 6(2) + 4 .... plug in y = 2

0^2 = 2^2 - 6(2) + 4

0 = 4 - 6(2) + 4

0 = 4 - 12 + 4

0 = -4

We get a false statement. This is one counterexample showing the given equation is not true for all values of y.

6 0
3 years ago
Read 2 more answers
Pls help will give brainilist
Yuki888 [10]

Answer:

3. 26 problems left

4. $69.20

Step-by-step explanation:

1. First I divided 5 into 2 to get a decimal, 0.4, and then I multiplied 0.4 to 65.

0.4 x 65 = 26

2. It said that Luke paid 2.75 for himself and 6 other friends, which is 7 people. I then multiplied 2.75 x 7 and got 19.25. I then added 19.25 to the other amount of money, and got 69.20.

49.95 + 19.25 = 69.20

Hope this helps <3

8 0
2 years ago
How you use the Pythagorean theorem in 3D.
Olin [163]

Answer:

If the base of the prism has dimensions x and y, and the diagonal along the base is represented by c, then x² + y² = c². The longest diagonal in the solid, s, is the hypotenuse of the triangle formed by the sides c and the height of the solid, z. So we know that, c² + z² = s².

Step-by-step explanation:

4 0
3 years ago
A definite integral of f(x)dx on the interval a to b probably SHOULDN'T be used:
OLga [1]
= cos( -x ) * [ - sin( - x ) ] = cosx * sinx ;
cosx * sin x is the right answer !
6 0
3 years ago
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