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4 years ago

Mrs Low has some money to buy plates and bowls for her new house.

Mathematics

1 answer:

jekas [21]4 years ago

8 0

Answer:

78=p

$150

$20

6 bowls

Step-by-step explanation:

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What is 12 1/3-10 11/12

Brut [27]

Answer:

1 5/12

Step-by-step explanation:

12 1/3 - 10 11/12

We need to get a common denominator of 12

12 1/3 * 4/4 - 10 11/12

12 4/12 - 10 11/12

We need to borrow from the 12 (the whole number) because the 2nd fraction is bigger than the first

12 becomes 11 and the 1 becomes 12/12

11+ (12/12 + 4/12) - 10 11/12

11 16/12 - 10 11/12

Subtract the whole numbers

11-10 =1

Subtract the fractions

16/12 - 11 /12 = 5 /12

We are left with 1 5/12

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3 years ago

How many centimeters are in 15 meters

pav-90 [236]

15 x 100= 1500 centimeters

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3 years ago

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A box with a square base and an open top is being constructed out of A cm2 of material. If the volume of the box is to be maximi

viktelen [127]

Answer:

Side length = $\sqrt{\frac{A}{3} }$ cm , Height = $\frac{1}{2} \sqrt{\frac{A}{3} }$ cm , Volume = $\frac{A\sqrt{A}}{6\sqrt{3} }$ cm³

Step-by-step explanation:

Assume

Side length of base = x

Height of box = y

total material required to construct box = A ( given in question)

So it can be written as

A = x² + 4xy

4xy = A - x²

$y = \frac{A - x^{2} }{4x}$

Volume of box = Area x height

V = x² ₓ y

V = x² ₓ ( $\frac{A - x^{2} }{4x}$ )

V = $\frac{Ax - x^{3} }{4}$

To find max volume put V' = 0

So taking derivative equation becomes

$\frac{A - 3 x^{2} }{4} = 0$

A = 3 $x^{2}$

$x^{2}$ = $\frac{A}{3}$

x = $\sqrt{\frac{A}{3\\} }$

put value of x in equation 1

y = $\frac{A - \frac{A}{3} }{4\sqrt{\frac{A}{3} } }$

y = $\frac{2 \sqrt{\frac{A}{3} } }{4 \sqrt{\frac{A}{3} } }$

y = $\frac{1}{2} \sqrt{\frac{A}{3} }$

So the volume will be

V = $x^{2}$ × y

Put values of x and y from equation 2 & 3

V = $\frac{A}{3} (\frac{1}{2} \sqrt{\frac{A}{3} } )$

V = $\frac{A\sqrt{A}}{6\sqrt{3} }$

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4 years ago

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frutty [35]

The first one does.

Hope this helps!

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