All categories

4 years ago

What is the speed of a wave that has a frequency of 3100 Hz and a wavelength of 0.012 m?

Physics

1 answer:

babymother [125]4 years ago

4 0

Answer:

v = 37.2 m/s

Explanation:

Given,

The frequency of the wave, f = 3100 Hz

The wavelength of the wave, λ = 0.012 m

The velocity of the propagation of the wave, v = ?

The relationship between the frequency, wavelength, and velocity of a wave is given by the formula

v = f x λ m/s

Substituting the values in the above equation

v = 3100 Hz x 0.012 m

= 37.2 m/s

Hence, the speed of the wave is, v = 37.2 m/s

You might be interested in

A car going 50 mph accelerates to pass a truck. Five seconds later the car is

Alex

The vehicle accelerates at 2.648 m/s².

We have:

Initial velocity, u = 50 miles per hour = 22.352 m/s

final velocity, v = 80 miles per hour = 35.762 m/s

Time, t = 5 seconds

The time in hours is:

t = 5 seconds

Now, the acceleration of the car can be calculated using the formula:

v = u + at

35.762 = 22.352 + a(5)

a(5) = 30

a = 2.682 m/s²

From the calculations above, the acceleration of the car is 2.682 m/s².

Ler more about acceleration here:

brainly.com/question/605631

#SPJ9

3 0

2 years ago

A wave with a period of 0.008 second has a frequency of

rodikova [14]

D. 125 Hz
$f = \frac{1}{t} = \frac{1}{0.008} \\ = 125hz$

4 0

4 years ago

Which has a greater mechanical advantage. a doorknob or screwdriver?

Brums [2.3K]

Answer:

screwdriver should be the awnser is what I think

6 0

3 years ago

Protons, neutrons, electrons, and a nucleus are

tatuchka [14]

It would be Atoms, they’re all made up of these tiny particles

8 0

3 years ago

A cyclotron is designed to accelerate protons (mass 1.67 x 10^-27 kg) up to a kinetic energy of 2.5 x 10^-13 J. If the magnetic

Dafna11 [192]

Answer:

24 cm

Explanation:

Given:

Mass of proton = 1.67 × 10⁻²⁷ Kg

kinetic energy = 2.5 × 10⁻¹³ J

magnetic field in the cyclotron, B = 0.75 T

Now,

Kinetic energy = $\frac{1}{2}mv^2$ = 2.5 × 10⁻¹³ J

where, v is the velocity of the electron

$\frac{1}{2}\times1.67\times10^{-27}\times v^2$ = 2.5 × 10⁻¹³ J

v² = 2.99 × 10¹⁴

v = 1.73 × 10⁷ m/s

also,

centripetal force = magnetic force

$\frac{mv^2}{r}$ = qvB

q is the charge of the electron

r is the radius of the dipole magnets

on substituting the respective values, we get

$\frac{1.67\times10^{-27}\times1.73\times10^7}{r}$ = 1.6 × 10⁻¹⁹ × 0.75

r = 0.2408 m ≈ 24 cm

Hence, the correct answer is 24 cm

6 0

3 years ago