Answer:
F = 3.6 10⁶ N
Explanation:
The expression for the electric force is
F =
in this case it indicates that the charge q1 is doubled
q₁ = 2 3 10⁻³ C
q₁ = 6 10⁻³ C
let's reduce the magnitudes to the SI system
q₂ = 6 10⁻³ C
r = 0.3 m
let's calculate
F = 9 10⁹ 6 10⁻³ 6 10⁻³ / 0.3²
F = 3.6 10⁶ N
Answer:
only E is true
Explanation:
A) to find out if it would fall 4x as fast by 2x the time we can look at the formula for free fall:
for free fall the Y = g where Y is the distance fallen, g is gravity and t is time
so since the rate at which an object falls is the same (gravity stays the same) it will not fall faster with any alteration
B) An object would fall half the distance if you double the time
here we may need to check with an example:
lets say we fall for 2 seconds in the first and 4 in the second:
Y= 1/2 (9.8) (2)^2 gives 19.6m fallen
Y= 1/2 (9.8) (4)^2 gives 78.4m fallen
from this we can see that doubling the time does not half the distance
C) all objects fall at the same rate no matter their mass so this statement is false
D) from the example above we see again that doubling time does not double the distance
E) this statement is true
Answer:
I₃ /I₀ = 25%
Explanation:
For this exercise let's use Malus's law
I = I₀ cos² θ
where tea is the angle between the two polarizers.
When the polarized light passes the first polarizer, the intensity is constant if it is in the direction of polarization.
I₁ = I₀
the light transmitted by the second polarizer is
I₂ = I₁ cos² θ
I₂ = I₀ cos² 45
I₂ = I₀ 0.5
this light is polarized 45º with respect to the first polarizer
Now let's examine the third polarizer, it is indicated that it has an angle of 90º with respect to the first polarizer, the angle with respect to the second polarizer is
θ = 90 - 45
θ = 45º
so the polarizer is at an angle of 45º
let's use Maus's law
I₃ = I₂ cos² 45
I₃ = I₀ 0.5 cos² 45
I₃ = I₀ 0.25
the light that passes through the system is
I₃ /I₀ = 0.25
as a percentage we multiply by 100
I₃ /I₀ = 25%
Answer:
The acceleration is about 9.8 m/s2 (down) when the ball is falling.
Explanation:
The ball at maximum height has velocity zero
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.8 m/s² (positive downward and negative upward)
The accleration 9.8 m/s² will always be acting on the body in opposite direction when the body is going up and in the same direction when the body is going down. The acceleration on the body will never be zero