Ok, so one way is like your way
so
if we test some numbers
for x=10
we get about 12.3/10≈1.2
for x=100000
we get 1522.03/100000≈0.01522
the top number keeps getting smaller reletive to bottom number
when x=1000000000
we get 8899.68/1000000000≈0.000009
we notice the bottom number is increaseing at a faster rate that the botom one
when x approaches infinity,the bottom number will be so big it will become a fraction that evaluates to basically zero becuase it evaluates to a very small number that is negligible
<h3>
Answer: 45</h3>
The value is approximate.
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Explanation:
Focus on the upper triangle.
Label the unknown horizontal side as y
Use the pythagorean theorem to solve for y
a^2+b^2 = c^2
10^2 + y^2 = 26^2
100+y^2 = 676
y^2 = 676-100
y^2 = 576
y = sqrt(576)
y = 24
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Now move to the bottom triangle
With respect to the reference angle, the side y = 24 is opposite this. The hypotenuse is unknown.
Use the sine rule to connect the two and solve for x
sin(angle) = opposite/hypotenuse
sin(32) = y/x
sin(32) = 24/x
x*sin(32) = 24
x = 24/sin(32)
x = 45.2899179551967 which is approximate
x = 45 rounding to the nearest whole number
Side x is approximately 45 cm long.
Note: make sure your calculator is in degree mode.
Answer:
It is stretch.
I hope it helps a little bit.
The given matrix equation is,
.
Multiplying the matrices with the scalars, the given equation becomes,
![\left[\begin{array}{cc}1.5x&9\\12&6\end{array}\right] +\left[\begin{array}{cc}y&4y\\3y&2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right] \\](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1.5x%269%5C%5C12%266%5Cend%7Barray%7D%5Cright%5D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dy%264y%5C%5C3y%262y%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dz%26z%5C%5C6z%262%5Cend%7Barray%7D%5Cright%5D%20%20%5C%5C%20%20)
Adding the matrices,
![\left[\begin{array}{cc}1.5x+y&9+4y\\12+3y&6+2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right] \\](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1.5x%2By%269%2B4y%5C%5C12%2B3y%266%2B2y%5Cend%7Barray%7D%5Cright%5D%20%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dz%26z%5C%5C6z%262%5Cend%7Barray%7D%5Cright%5D%20%20%5C%5C%20)
Matrix equality gives,

Solving the equations together,

We can see that the equations are not consistent.
There is no solution.