Answer:
Please see attachment
Step-by-step explanation:
Please see attachment
Answer: You will need to know that the volume of a cone can be calculated using the formula V = 1/3*Pi*r^2*h, where V is the volume, r is the radius and h is the height. Next substitute the radius and volume into the formula. After this divide the volume by 1/3, r^2 and Pi to give the height of the cone.
H = V(3) / R^2(Pie)
We have been given that the distribution of the number of daily requests is bell-shaped and has a mean of 38 and a standard deviation of 6. We are asked to find the approximate percentage of lightbulb replacement requests numbering between 38 and 56.
First of all, we will find z-score corresponding to 38 and 56.


Now we will find z-score corresponding to 56.

We know that according to Empirical rule approximately 68% data lies with-in standard deviation of mean, approximately 95% data lies within 2 standard deviation of mean and approximately 99.7% data lies within 3 standard deviation of mean that is
.
We can see that data point 38 is at mean as it's z-score is 0 and z-score of 56 is 3. This means that 56 is 3 standard deviation above mean.
We know that mean is at center of normal distribution curve. So to find percentage of data points 3 SD above mean, we will divide 99.7% by 2.

Therefore, approximately
of lightbulb replacement requests numbering between 38 and 56.
Answer: F
Step-by-step explanation:
1+2+...+n = n*(n+1)/2 for all natural numbers n.
Left-hand-side = (5+1)+(5+2)+...+(5+10)=5*10+10*(10+1)/2=50+55=105
Right-hand-side = (4)+(4+1)+...+(4+9)=4*10+9*(9+1)/2=40+45=85
105≠85
The equation is false
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