The frustum can be considered as consisting of a square pyramid, less the
cut volume.
- The mass of the stand, is approximately 18.60905 kg
Reasons:
The given parameter of the frustum are;
The density of the frustum, ρ = 85 g/cm³
Height of pyramid, h = 9 cm
Side length of base = 10 cm
Height of frustum
By proportional shapes, the side length of the top of the frustum can be found as follows;



B₁ = 10², B₂ = 
Therefore;

The volume of the stand, V ≈ 218.93 cm³
Mass = Volume × Density
∴ Mass of the stand, m = 218.93 cm³ × 85 g/cm³ = 18,609.05 grams = 18.60905 kg.
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Answer:
41
Step-by-step explanation:
1.65 + 0.85x= $20
0.85x=$18.35
x=21 10/17
first you write the equation
then you have to subtract 1.65 from the equation but you also have to subtract it from 20
then you divide 0.85 from 0.85x and from the 18.35 left over from subtracting 1.65 from 20
then you should get x=21 10/17 (simplified) but the decimal form is a ongoing fraction so you can just round it up to the nearest hundredth
Since the interior is 170 the exteriro must be 10 degrees. There is a total of 360 degrees so 360/10=36 or 36 sides.