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3 years ago

I don’t know how to do this. HELP!

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

3 0

Answer:

1/4

Step-by-step explanation:

coins have 2 sides, tails and heads, so for it to land on tails is a 1/2 chance. Dice have 6 sides and 1,3,5 are all odd so its a 3/6 chance. Simplify 3/6 to 1/2 and multiply by 1/2 to get 1/4. im not sure, its my guess.

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Find K: mx=p(z/x+k + 2s/y)

ivann1987 [24]

Answer:

$-\frac{2s}{y} -\frac{z}{x} +\frac{mx}{p} =k$

Step-by-step explanation:

$mx=p(\frac{z}{x} +k+\frac{2s}{y} )$ - Divide by p

$\frac{mx}{p} =(\frac{z}{x} +k+\frac{2s}{y} )$ - Subtract the 2 fractions

$-\frac{2s}{y} -\frac{z}{x} +\frac{mx}{p} =k$

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3 years ago

Polynomial Equation question<br>(Screenshot included)

Illusion [34]

$y = {x}^{3} - 4 {x}^{2} - 45x \\ y = x( {x}^{2} - 4x - 45) \\ y = x(x + 5)(x - 9) \\ x = 0, - 5,9$
So, to find our x-intercepts, y must be zero
$0 = x \\ \\ 0 = (x + 5) \\ - 5 = x \\ \\ 0 = (x - 9) \\ 9 = x$
ANSWER: (0,0) (-5.0) (9,0) are your x-intercepts

6 0

3 years ago

You play basketball at your school's

vaieri [72.5K]

Answer:

20 + 2x = 4x

Step-by-step explanation:

So you are setting the two expressions equal to each other.

buying a membership card and paying each time looks like this: 20 + 2x where x is the number of times you go to the gym. 20 dollars base then 2 each time you go.

4 each time you go is just 4x

so just set the two equal to each other.

20 + 2x = 4x

If you solve it you will get x = something, which would be the number of times to make the two equal.

8 0

3 years ago

The domain of: x+3 under square root

Gennadij [26K]

Answer:

All real numbers except where x<-3

Step-by-step explanation:

Values of x that make negatives under even radicals are not part of the domain. Any value of x that is less than -3 would make a negative under the square root, so those are not included in the domain.

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3 years ago

Greg is trying to solve a puzzle where he has to figure out two numbers, x and y. Three less than two-third of x is greater than

Fittoniya [83]

Inequation 1:

$\frac{2}{3}x-3 \geq y$

to plot the pairs (x, y) for which the inequation holds, draw the line $y=\frac{2}{3}x-3$

then pick a point in either side of the line. If that point is a solution of the inequation, than color that region of the line, if that point is not a solution, then color the other part of the line.

we do the same for the second inequation. Then the solution, is the region of the x-y axes colored in both cases.

inequation 2:

$y+ \frac{2}{3}x\ \textless \ 4$

$y\ \textless \ - \frac{2}{3} x+ 4
$

draw the lines

i) $y=\frac{2}{3}x-3$ use points (0, -3), (3, -1)

ii) $y=- \frac{2}{3} x+ 4$ use points ( 0, 4), (3, 2)

let's use the point P(3, 3) to see what region of the lines need to be coloured:

$\frac{2}{3}x-3 \geq y$ ;
$\frac{2}{3}(3)-3 \geq 3$
$2-3 \geq 3$ , not true so we color the region not containing this point

$y+ \frac{2}{3}x\ \textless \ 4$
$(3)+ \frac{2}{3}(3)\ \textless \ 4$
$3+ 5\ \textless \ 4$ not true, so we color the region not containing the point (3, 3)

The graph representing the system of inequalities is the region colored both red and blue, with the blue line not dashed, and the red line dashed.

4 0

3 years ago