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3 years ago

4/13÷7/8 in simplest form

1 answer:

5 0

Hey There!

1) Make the second fraction a reciprocal. $\frac{8}{7}$

2) Now multiply $\frac{4}{13} * \frac{8}{7}$

3) Your answer would be $\frac{32}{91}$

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A zoo had 2250 visitors on Friday and 4725 on Saturday. What was the percent of increase of the number of visitors on Saturday o

NARA [144]

4725-2250= 2475
2475/2250 x100= 110
It increased by 110%

7 0

3 years ago

It costs $3 to bowl a game and $2 for shoe rental.

gulaghasi [49]

Expression: 3g+2
cost of 8 games: 3*8=24+2= 26

3 0

3 years ago

What is the degree of the monomial? 3x^10

zysi [14]

The degree is 0. I don't know how to solve it I just used a website that allows you to answer things like this. <span />

8 0

3 years ago

Assume that the radius r of a sphere is expanding at a rate of 40 cm/min. The volume of a sphere is V = 4 3 πr3 and its surface

Scrat [10]

Answer:

The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.

Step-by-step explanation:

The area of a sphere is given by the following formula:

$A = 4\pi r^{2}$

In which A is the area, measured in cm², and r is the radius, measured in cm.

Assume that the radius r of a sphere is expanding at a rate of 40 cm/min.

This means that $\frac{dr}{dt} = 40$

Determine the rate of change in surface area when r = 20 cm.

This is $\frac{dA}{dt}$ when $r = 20$ . So

$A = 4\pi r^{2}$

Applying implicit differentiation.

We have two variables, A and r, so:

$\frac{dA}{dt} = 8r\pi \frac{dr}{dt}$

$\frac{dA}{dt} = 8*20\pi*40$

$\frac{dA}{dt} = 20106.19$

The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.

6 0

3 years ago

50 POINTS!

nignag [31]

Answer:

im gussing sorry if its wrong :(

Step-by-step explanation:

1=a

2=d

3=b

4=c

4 0

3 years ago

Read 2 more answers