2r^6+11r^3-13 help me please!!!!!
1 answer:
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Answer:
c. 0.0498
Step-by-step explanation:
First of all, let us find the number of four digit numbers possible.
There are 4 digits and let us have a look at the possibility of each digit.
Number of possible options for Unit's digit = 10
Number of possible options for ten's digit = 10
Number of possible options for hundred's digit = 10
Number of possible options for thousand's digit = 9 (because 0 can not be there to make it a 4 digit number)
Total number of possible outcomes =
As per the given condition, unit's digit is 7.
So, number of possible options for unit's digit = 1
Number of possible options for thousand's digit = 8 (7 and 0 can not be there to make it a 4 digit number)
Number of possible options for hundred's digit = 8 (7 and one digit used in thousand's place can not be there)
Number of possible options for ten's digit = 7 (7, two digits used at thousand's and hundred's places)
Number of possible outcomes as per given conditions =
Formula for probability of an event E can be observed as:
Answer:
a) (0.576, 0.624)
Step-by-step explanation:
Given that the sample proportion (p) = 60% = 0.6, sample size (n) = 900, confidence (C) = 85%
α = 1 - C = 1 - 0.85 = 0.15
α/2 = 0.075
The z score of α/2 (0.075) corresponds with the z score of 0.425 (0.5 - 0.075) which is equals to 1.44, hence
The margin of error (E) is:
The confidence interval = p ± E = 0.6 ± 0.024 = (0.576, 0.624)