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Grace [21]
3 years ago
6

Find the value of the expression

Mathematics
1 answer:
Ivenika [448]3 years ago
3 0

Answer:

5

Step-by-step explanation:

3+16/2*17/4/17

3+8*17/4/17

3+136/4/17

3+34/17

3+2

5

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Help me find like terms, (multiple choice).
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Answer:

Like terms:

\frac{1}{2}x^{2}

1.25x²

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Step-by-step explanation:

Like terms are terms that have the same variable to the same exponent.  In this case, the only like terms are those with the variable 'x' to the exponent of '2', or x².  This would include the terms:

\frac{1}{2}x^{2}

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At the beginning of a population study, the population of a large city was 1.65 million people. Three years later, the populatio
Maksim231197 [3]

Answer:

C. 1.8027

Step-by-step explanation:

The exponential population growth model is given by:

P(t) = P_{0}e^{rt}

In which P(t) is the population after t years, P_{0} is the initial population and r is the growth rate.

At the beginning of a population study, the population of a large city was 1.65 million people. Three years later, the population was 1.74 million people.

This means that P_{0} = 1.65, P(3) = 1.74

Applying this to the equation, we find r. So

P(t) = P_{0}e^{rt}

1.74 = 1.65e^{3r}

e^{3r} = \frac{1.74}{1.65}

e^{3r} = 1.0545

Applying ln to both sides

\ln{e^{3r}} = \ln{1.0545}

3r = \ln{1.0545}

r = \frac{\ln{1.0545}}{3}

r = 0.0177

So

P(t) = 1.65e^{0.0177t}

What would be the population of the city 5 years after the start of the population study?

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So the correct answer is:

C. 1.8027

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