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labwork [276]
3 years ago
9

The Atlanta Journal Constitution conducted a survey of 900 registered voters to determine which voting method they prefer. The A

JC found 60% favored voting on paper ballots they filled themselves (as opposed to voting with a computer). Find a confidence interval for the proportion of all registered voters that favor at 85% confidence level. a) (0.576, 0.624) b) (0.376, 0.424) c) (0.583, 0.617) d) (0.586, 0.614)
Mathematics
1 answer:
photoshop1234 [79]3 years ago
7 0

Answer:

a) (0.576, 0.624)

Step-by-step explanation:

Given that the sample proportion (p) = 60% = 0.6, sample size (n) = 900, confidence (C) = 85%

α = 1 - C = 1 - 0.85 = 0.15

α/2 = 0.075

The z score of α/2 (0.075) corresponds with the z score of 0.425 (0.5 - 0.075) which is equals to 1.44, hence z_\frac{\alpha }{2} =1.44

The margin of error (E) is:

E=z_\frac{\alpha }{2} *\sqrt{\frac{p(1-p)}{n} } =1.44*\sqrt{\frac{0.6(1-0.6)}{900} } = 0.024

The confidence interval = p ± E = 0.6 ± 0.024 = (0.576, 0.624)

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Which statement is correct?
Arisa [49]

Answer:

2.06 \times 10^-^2 = 206

1.88 \times 10^-^1 = 18.8

206 \times 18.8 = 3,872.8

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2.3 \times 10^-^5  = 230,000

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Step-by-step explanation:

Which statement is correct?

(2.06x102x1.88 x 10-1) <7.69x 10

2.3x10-5

(2.06 x 10-2)(1.88 x 10-1) 7.69x 10-

2.3x10-5

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(2.06x 10-2X(1.88x 10-1)-7.69x104

2.3x10-5

Given that;

2.06 \times 10^-^2 = 206

1.88 \times 10^-^1 = 18.8

206 \times 18.8 = 3,872.8

7.69 \times 10^-^2 = 769

2.3 \times 10^-^5  = 230,000

=\frac{769}{230000}

= 0.00334

therefore,

3,872.80 > 0.00334

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Answer:

=> 6x-1=5

=>6x=6

=>x=1

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